Merge two sorted linked lists and return it as a sorted list. The list should be made by splicing together the nodes of the first two lists. Example 1:Input:l1=[1,2,4],l2=[1,3,4]Output:[1,1,2,3,4,4] Example 2:Input:l1=[],l2=[]Output:[] Example 3:Input:l1=[],l2=[0...
Quest:Merge two sorted linked lists and return it as a new list. The new list should be made by splicing together the nodes of the first two lists. 合并两个有序数列 题目给出的原型类 publicclassListNode {intval; ListNode next; ListNode(intx) { val =x; } }publicListNode mergeTwoLists(L...
链表(Linked List)是一种常用的基础数据结构,它与数组、栈、队列、树、图等其他数据结构在存储方式、性能、使用场景等方面有着各自的特点和优势。以下是链表与其他几种数据结构的主要特点比较: 链表与数组 存储方式:链表通过节点(Node)的形式存储数据,每个节点包含数据本身和一个指向下一个节点的指针(或者在双向链表...
需要遍历 list2 中的全部 O(|list2|) 个结点 空间复杂度:O(1) 只需要维护常数个额外变量 代码(Python3) # Definition for singly-linked list. # class ListNode: # def __init__(self, val=0, next=None): # self.val = val # self.next = next class Solution: def mergeTwoLists(self, list...
Merge two sorted linked lists and return it as a sorted list. The list should be made by splicing together the nodes of the first two lists. Example 1: Input: l1 = [1,2,4], l2 = [1,3,4] Output: [1,1,2,3,4,4] Example 2: ...
Merge two sorted linked lists and return it as a new list. The new list should be made by splicing together the nodes of the first two lists. Example: Input: 1->2->4, 1->3->4 Output: 1->1->2->3->4->4 题意:将所给的两个已排好序的链表,合成一个有序的链表 ...
Merge two sorted linked lists and return it as a new list. The new list should be made by splicing together the nodes of the first two lists. 题目大意:合并两个有序的链表 思路:通过比较两个链表的节点大小,采用尾插法建立链表。 代码如下: ...
1、题目 Merge two sorted linked lists and return it as a new list. The new list should be made by splicing together the nodes of the first two lists. 合并2个有序链表 2、代码实现 ... 1、题目 Merge two sorted linked lists and return it as a new list. The new list should be made...
Merge two sorted linked lists and return it as a new list. The new list should be made by splicing together the nodes of the first two lists. 翻译:合并两个排好序的链列,并将其作为新链表返回。新链表应通过将前两个列表的节点拼接在一起。
Merge two sorted linked lists and return it as a new list. The new list should be made by splicing together the nodes of the first two lists. 依次拼接 复杂度 时间O(N) 空间 O(1) 思路 该题就是简单的把两个链表的节点拼接起来,我们可以用一个Dummy头,将比较过后的节点接在这个Dummy头之后。