改进mergeTwoLists方法,以在开始时检查空链表。 class ListNode: def __init__(self, x): self.val = x self.next = None # 改进后的将给出的数组转换为链表的函数 def linkedlist(list): if not list: # 检查列表是否为空 return None # 空列表返回None head = ListNode(list[0]) cur = head for...
Merge two sorted linked lists and return it as a new list. The new list should be made by splicing together the nodes of the first two lists. 解题思路: 1)定义l,每次l指向两个链表中小的那个节点,定义head为头指针,定义ptr,将l依次连成链表 2)两个链表均不为空,将其小的值赋给l 3)将其中节...
需要遍历 list2 中的全部 O(|list2|) 个结点 空间复杂度:O(1) 只需要维护常数个额外变量 代码(Python3) # Definition for singly-linked list. # class ListNode: # def __init__(self, val=0, next=None): # self.val = val # self.next = next class Solution: def mergeTwoLists(self, list...
Merge two sorted linked lists and return it as a new list. The new list should be made by splicing together the nodes of the first two lists. Example: Input: 1->2->4, 1->3->4 Output: 1->1->2->3->4->4 1. 2. # Definition for singly-linked list. # class ListNode(object)...
Merge two sorted linked lists and return it as a new list. The new list should be made by splicing together the nodes of the first two lists. Example: Input: 1->2->4, 1->3->4 Output: 1->1->2->3->4->4 和88. Merge Sorted Array类似,数据结构不一样,这里是合并链表。
Merge two sorted linked lists and return it as a sorted list. The list should be made by splicing together the nodes of the first two lists. Example 1: Input: l1 = [1,2,4], l2 = [1,3,4] Output: [1,1,2,3,4,4] Example 2: ...
Merge two sorted linked lists and return it as a new list. The new list should be made by splicing together the nodes of the first two lists. 示例: 输入:1->2->4, 1->3->4 输出:1->1->2->3->4->4 解题思路: 迭代和递归都能解题。无非是依次将两个链表每个节点的值对比,取出值较小...
链接:https://leetcode-cn.com/problems/merge-two-sorted-lists 著作权归领扣网络所有。商业转载请联系官方授权,非商业转载请注明出处。 和并归排序的思路差不多,不过需要注意的是在移动指针的时候不要丢失指针位置,一个是头指针的记录,另一个就是节点的当前位置,再一个就是两个链表可能出现不等长的情况,这时候...
You are given the heads of two sorted linked listslist1andlist2. Merge the two lists into onesortedlist. The list should be made by splicing together the nodes of the first two lists. Return the head of the merged linked list.
1. 题目描述 Merge two sorted linked lists and return it as a new sorted list. The new list ...