Input:1->2->4, 1->3->4Output:1->1->2->3->4->4 因为没有空间要求,所以想到ListNode*head = new ListNode(INT_MIN);重新定义一个链表,分别比较两个有序链表的大小然后将所在结点一次加入到定义的新链表中。 最后注意释放头结点空间。 /** * Definition for singly-linked list. * struct ListNode...
https://leetcode.com/problems/merge-k-sorted-lists/ 题目: Merge k sorted linked lists and return it as one sorted list. Analyze and describe its complexity. 思路: 注意要保存合并后新表头集合,合并迭代退出的条件是表头集合size为1。空间复杂度为O(n),时间复杂度为O(nlogn)。 设迭代合并链表次数为...
3. divide and conquer, like merge sort, use the dichotomy, divide the whole problem in half and half... first partition the list, than merge two list. /*** Definition for singly-linked list. * public class ListNode { * int val; * ListNode next; * ListNode(int x) { val = x; }...
注意vector为空时表示为[],而不是[{}],而后者是大小为1的vector,其中元素是空指针 放入优先权队列时进行判断是否为空 放入优先权队列的元素是ListNode *, 而不是int,主要是保持原有链表的地址,避免地址失效,而且放入int话,之后又重新new ListNode(int)开销还是比较大的. 对放入优先权队列中得ListNode*要定义一...
//leetcode.com/subscribe/) for the access to premium questions.) ## Algorithms * [Bit Manipulation](https://github.com/kamyu104/LeetCode#bit-manipulation) * [Array](https://github.com/kamyu104/LeetCode#array) * [String](https://github.com/kamyu104/LeetCode#string) * [Linked List](...
Problem 1: Merge Intervals Problem 2: Insert Interval5. Cyclic SortProblem 1: Find All Numbers Disappeared in an Array Problem 2: Find the Duplicate Number6. In-place Reversal of Linked ListProblem 1: Reverse Linked List Problem 2: Reverse Nodes in k-Group...
76 + II: Don’t use heap sort for linked list 77 + 78 + III: Don’t use unstable algorithm on array with the same key 79 + 80 + IV: Don’t use insertion sort on large inversion array Diff for: 数据结构基础/作业/HW3 Note.md +120 Original file line numberDiff line...
今天的笔记包含多路归并(K-way merge)与拓扑排序(Topological Sort)类型下的X个题目。其中“多路归并”在leetcode上的编号和题名分别是: 21 - 合并两个有序列表 23 - 合并k个排序列表 373 - 查找和最小的k对数字 378 - 有序矩阵中第k小的元素
LeetCode---23. Merge k Sorted Lists 合并k个有序列表...LeetCode 23 Merge k Sorted Lists Problem: Merge k sorted linked lists and return it as one sorted list. Analyze and describe its complexity. Example: Input: [ 1->4->5, 1->3->4, 2->6 ] Output: 1->1->2->3->4-......
I liked the core of your solution of creating a fakehead. But, unfortunately it is not complete. Below is the complete non-recursive solution for the above problem in JAVA: public class MergingTwoSortedLists { private class ListNode { ...