Merge k sorted linked lists and return it as one sorted list. Analyze and describe its complexity. 合并k个有序链表。 二、解题报告 解法一:两两合并 由于前面刚刚做过《LeetCode 21 - Merge Two Sorted Lists》,看到这个题的第一反应就是两两合并,还可以直接调用mergeTwoLists()。 classSolution{public:...
LeetCode —— Merge k Sorted Lists 1/*2** 算法的思路:3 ** 1.将k个链表的首元素进行建堆4 ** 2.从堆中取出最小的元素,放到链表中5 ** 3.如果取出元素的有后续的元素,则放入堆中,若没有则转步骤2,直到堆为空6*/789#include <stdio.h>101112structListNode13{14intval;15structListNode *next;1...
## LeetCode 21 合并链表 ## 引用官方代码,定义结点类 class ListNode: def __init__(self, x): self.val = x self.next = None 将数组转换为链表,也可以理解为链表的创建(官网不给出): ## 将给出的数组,转换为链表 def linkedlist(list): head = ListNode(list[0]) ## 列表的第一个元素。这里...
next = list2; } // 返回合并后的链表的头结点 head_pre.next } } 题目链接: Merge Two Sorted Lists : leetcode.com/problems/m 合并两个有序链表: leetcode-cn.com/problem LeetCode 日更第 52 天,感谢阅读至此的你 欢迎点赞、收藏鼓励支持小满...
Merge k sorted linked lists and return it as one sorted list. Analyze and describe its complexity. 提议很简单,就是归并排序。 首先想到的即使逐个归并得到最终的结果,但是会超时,这是因为这种会造成数组的size大小不一样,导致归并排序的时间变长; ...
leetcode 21. Merge Two Sorted Lists Merge two sorted linked lists and return it as a new list. The new list should be made by splicing together the nodes of the first two lists. Example: Input: 1->2->4, 1->3->4 Output: 1->1->2->3->4->4...
The sum of lists[i].length will not exceed 104. #链表总长度不会超过104. 分析 之前做过两个有序链表的排序插入Leetcode21 Merge Two Sorted Lists。当时有暴力循环迭代的方法,还有递归的方法。每次加入一个元素,然后对剩下的元素继续调用函数进行排序插入。
publicListNodemergeTwoLists(ListNodel1,ListNodel2){ListNodeh=newListNode(0);ListNodeans=h;while(l1!=null&&l2!=null){if(l1.val<l2.val){h.next=l1;h=h.next;l1=l1.next;}else{h.next=l2;h=h.next;l2=l2.next;}}if(l1==null){h.next=l2;}if(l2==null){h.next=l1;}returnans.next;...
Can you solve this real interview question? Merge k Sorted Lists - You are given an array of k linked-lists lists, each linked-list is sorted in ascending order. Merge all the linked-lists into one sorted linked-list and return it. Example 1: Inpu
* 题目: 21.Merge Two Sorted Lists * 来源:https://oj.leetcode.com/problems/merge-two-sorted-lists/ * 结果:AC * 来源:LeetCode * 博客: ***/ #include <iostream> using namespace std; struct ListNode{ int val; ListNode *next; ListNode...