改进mergeTwoLists方法,以在开始时检查空链表。 class ListNode: def __init__(self, x): self.val = x self.next = None # 改进后的将给出的数组转换为链表的函数 def linkedlist(list): if not list: # 检查列表是否为空 return None # 空列表返回None head = ListNode(list[0]) cur = head for...
next = list2; } // 返回合并后的链表的头结点 head_pre.next } } 题目链接: Merge Two Sorted Lists : leetcode.com/problems/m 合并两个有序链表: leetcode-cn.com/problem LeetCode 日更第 52 天,感谢阅读至此的你 欢迎点赞、收藏鼓励支持小满...
1publicListNode mergeTwoLists(ListNode l1, ListNode l2){2if(l1 ==null)returnl2;3if(l2 ==null)returnl1;4if(l1.val <l2.val){5l1.next =mergeTwoLists(l1.next, l2);6returnl1;7}else{8l2.next =mergeTwoLists(l1, l2.next);9returnl2;10}11} 答案复杂度: 时间:O(N+M) 空间:O(N+M...
1importjava.util.Comparator;2importjava.util.PriorityQueue;34//public class LeetCode23 为测试代码5publicclassLeetCode23{6publicstaticvoidmain(String[] args) {7ListNode[] lists=newListNode[3];8ListNode a1=newListNode(1);9ListNode a2=newListNode(4);10ListNode a3=newListNode(7);11a1.next=a2;12...
先不考虑Heap的时间复杂度,则上述函数的操作是O(lg n)的。 但是将Heap的操作时间复杂度加入计算后发现,函数进行了n次add()和n次poll()。add和poll的负责度都是O(lg n),所以上述总体时间复杂度是:2n(lg n),也就是O(n*lgn)。 2、使用Merge two sorted lists的方法来 ...
head2=head2.nexttail=tail.nextifhead1:tail.next=head1ifhead2:tail.next=head2returndummy.next# 方法二 非递归classSolution(object):defmergeKLists(self,lists):""" :type lists: List[ListNode] :rtype: ListNode """ifnotlists:returnNonewhilelen(lists)>1:new_lists=[]foriinrange(0,len(lis...
Merge Two Sorted Lists Merge two sorted linked lists and return it as a new list. The new list should be made by splicing together the nodes of the first two lists. C++代码如下: #include<iostream>#include<new>usingnamespacestd;//Definition for singly-linked list.structListNode...
Merge the sorted halves back together: `[0, 1, 2, 3, 4, 5]` Time Complexity of Merge Sort The time complexity of merge sort is O(n log n), where n is the number of elements in the array. This is because the merge sort algorithm divides the array into two halves at each recu...
LeetCode:Merge k Sorted Lists Mergeksorted linked lists and return it as one sorted list. Analyze and describe its complexity. 合并k个有序的链表,我们假设每个链表的平均长度是n。这一题需要用到合并两个有序的链表子过程 算法1: 最傻的做法就是先1、2合并,12结果和3合并,123结果和4合并,…,123....
0023. Merge K Sorted Lists 0024. Swap Nodes in Pairs 0025. Reverse Nodes in K Group 0026. Remove Duplicates From Sorted Array 0027. Remove Element 0028. Find the Index of the First Occurrence in a String 0029. Divide Two Integers 0030. Substring With Concatenation of All Words 0031. Next...