heappush(free_rooms, intervals[0][1]) # 从第二个会议开始遍历 for i in intervals[1:]: # 如果当前会议的开始时间大于等于最小堆中的最早结束时间 # 说明这个会议室可以被重复使用 # 因此我们可以移除堆顶元素(最早结束的会议室) if i[0] >= free_rooms[0]: heapq.heappop(free_rooms) # 将当前...
// Step 3: Scan the events and maintain the number of meeting rooms in use. int maxRooms = 0; int roomsInUse = 0; for (int[] event : events) { // Update the number of rooms in use roomsInUse += event[1]; // Update the maximum number of rooms needed maxRooms = Math.max(...
1classSolution {2publicintminMeetingRooms(int[][] intervals) {3//corner case4if(intervals ==null|| intervals.length == 0) {5return0;6}78//normal case9Arrays.sort(intervals, (a, b) -> a[0] - b[0]);10//sort by ending time11PriorityQueue<int[]> heap =newPriorityQueue<>(intervals...
Given an array of meeting time intervals consisting of start and end times[[s1,e1],[s2,e2],...](si < ei), find the minimum number of conference rooms required. For example, Given[[0, 30],[5, 10],[15, 20]], return2. 252. Meeting Rooms的拓展,同样给一个开会的区间数组,返回最少...
https://leetcode.com/problems/meeting-rooms-ii/description/ 解题方法: 先记录每个interval开始和结束所需要的房间数,当开始时,需要的房间数为1,而结束时,需要的房间数为-1; 再遍历一遍以上记录的数组,这样所需的房间数会随着以上的记录不断的变化,用一个变量去记录随时变化的房间数出现的最大值就是我们所求...
则可以复用房间if(startTimes[i]>=endTimes[endIndex]){// Reuse the room: move the endIndex to the next meetingendIndex++;}else{// If no room is available, we need a new oneroomCount++;}}// The room count will be the number of rooms we needreturnroomCount+1;// We need at least...
【LeetCode】253. Meeting Rooms II 解题报告(C++) id: fuxuemingzhu http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 排序+堆 日期 题目地址:https://leetcode-cn.com/problems/meeting-rooms/ 题目描述 Given an array of meeting time intervals consisting of start and end times[[s1,e1],[...
[Leetcode] Meeting Rooms 会议室 Meeting Rooms Given an array of meeting time intervals consisting of start and end times[[s1,e1],[s2,e2],...] (si < ei), determine if a person could attend all meetings. For example, Given[[0, 30],[5, 10],[15, 20]], return false....
0244-Shortest-Word-Distance-II 0245-Shortest-Word-Distance-III 0249-Group-Shifted-Strings 0250-Count-Univalue-Subtrees 0252-Meeting-Rooms 0253-Meeting-Rooms-II/cpp-0253 CMakeLists.txt main.cpp main2.cpp main3.cpp main4.cpp 0254-Factor-Combinations 0257-Binary-Tree-Paths ...
题目描述 题目描述 题解 提交记录 提交记录 代码 排序 不限 登录并分享题解 登录 9 1 2 › [[0,30],[5,10],[15,20]] [[7,10],[2,4]] Source 该题目是 Plus 会员专享题 感谢使用力扣!您需要升级为 Plus 会员来解锁该题目 升级Plus 会员...