LeetCode刷题系列—4.Median of Two Sorted Arrays 1.题目描述 英文版: There are two sorted arrays nums1 and nums2 of size m and n respectively. Find the median of the two sorted arrays. The overall run time complexity should be O(log (m+n)). You may assume nums1 and nums2 cannot ...
最后决定讲一道我个人觉得很有意思的一道题,那就是LeetCode上大名鼎鼎的Median of Two Sorted Arrays。这道题是一道非常经典并且有相当难度的二分查找问题,彻底理解和实现之后其他二分查找问题相信都会迎刃而解。 题目详情 原题如下: There are two sorted arrays nums1 and nums2 of size m and n respectively...
publicdoublefindMedianSortedArrays(int[] nums1,int[] nums2) {intn1 =nums1.length;intn2 =nums2.length;inttotal = n1 +n2;if(total % 2 == 1)//奇数情况{returnfindMiddle(nums1, nums2, n1, n2, (total/2 + 1)); }else{return(findMiddle(nums1, nums2, n1, n2, (total/2)) + fin...
There are two sorted arraysnums1andnums2of size m and n respectively. Find the median of the two sortedarrays. The overall run time complexity should be O(log (m+n)). Example 1: nums1 = [1, 3] nums2 = [2] The median is 2.0 Example 2: nums1 = [1, 2] nums2 = [3, 4] ...
Median of Two Sorted Arrays: Given two sorted arraysnums1andnums2of sizemandnrespectively, returnthe medianof the two sorted arrays. Example: Input: nums1 = [1,2,3,4,5], nums2 = [2,3,7] Output: 3.00000 Explanation: merged array = [1,2,2,3,3,4,5,7] and median is (3 + 3...
Find the Index of the First Occurrence in a String 找出字符串中第一个匹配项的下 Grandyang刷尽天下 90 0 25:07 [LeetCode] 5. Longest Palindromic Substring 最长回文子串 Grandyang刷尽天下 113 0 13:44 [LeetCode] 15. 3Sum 三数之和 Grandyang刷尽天下 14 0 15:22 [LeetCode] 22. ...
Leetcode-Hard 4. Median of Two Sorted Arrays 题目描述 有两个排序的数组nums1和nums2分别为m和n。 找到两个排序数组的中位数。总运行时间复杂度应为O(log(m + n))。 假设nums1和nums2不能都为空。 思路 将两个数组合并然后排序,根据合并后新数组长度来计算中位数...
LeetCode 3.Longest Substring Without Repeating-4.Median of Two Sorted Arrays. Characters 3. 无重复字符的最长子串 方法一:滑动窗口 AI检测代码解析 class Solution: def lengthOfLongestSubstring(self, s: str) -> int: d = {} # element:index ,element的位置...
There are two sorted arrays nums1 and nums2 of size m and n respectively. Find the median of the two sorted arrays. The overall run time complexity should be O(log (m+n)). Example1:nums1=[1,3]nums2=[2]Themedianis2.0Example2:nums1=[1,2]nums2=[3,4]Themedianis(2+3)/2=2.5...
首先理解题意两个关键点:有序数组和中位数 对于有序数组a,长度为m 如果m为奇数,则中位数为第m/2+1小的数; 如果m为偶数,则中位数为第m/2+1小与第m/2小的数的平均和; 对于有序数组a和b,长度分别为m和n 如果m+n为奇数,则两个数组的中位数为第(m+n)/2+1小的数 ...