最后我们来分析这个解法的复杂度,解法三我们每一次循环排除掉k/2个元素,所以时间复杂度是O(logk),而k是m+n的一半,所以时间复杂度为O(log(m+n)),没有用到额外空间,空间复杂度为O(1)。 classSolution{//解法三:相当于求两个有序数组的第k小数字publicdoublefindMedianSortedArrays(int[] nums1,int...
There are two sorted arrays A and B of size m and n respectively. Find the median of the two sorted arrays. The overall run time complexity should be O(log (m+n)). 解法一:保底做法,O(m+n)复杂度 按照归并排序的思路,先归并,再找中间值。 classSolution {public:doublefindMedianSortedArrays...
最后决定讲一道我个人觉得很有意思的一道题,那就是LeetCode上大名鼎鼎的Median of Two Sorted Arrays。这道题是一道非常经典并且有相当难度的二分查找问题,彻底理解和实现之后其他二分查找问题相信都会迎刃而解。 题目详情 原题如下: There are two sorted arrays nums1 and nums2 of size m and n respectively...
return findKth(nums1, m, nums2 + median, n- median, k - median); } } }; 代码二 class Solution { public: double findMedianSortedArrays(vector<int>& nums1, vector<int>& nums2) { if(nums1.size() > nums2.size()) return findMedianSortedArrays(nums2, nums1); if(nums1.size() ...
classSolution{public:doublefindMedianSortedArrays(vector<int>&nums1,vector<int>&nums2){intm=nums1.size(),n=nums2.size();if(m>n)returnfindMedianSortedArrays(nums2,nums1);intlow=0,high=m;while(left<=right){inti=low+(high-low)/2;intj=(m+n)/2-i;intleft1=(i==0)?INT_MIN:nums1...
Remove Duplicates from Sorted Array 删除有序数组中的重复项 Grandyang刷尽天下 56 0 09:59 [LeetCode] 1. Two Sum 两数之和 Grandyang刷尽天下 125 0 13:05 [LeetCode] 2. Add Two Numbers 两个数字相加 Grandyang刷尽天下 94 0 08:40 [LeetCode] 21. Merge Two Sorted Lists 合并两个有...
Can you solve this real interview question? Median of Two Sorted Arrays - Given two sorted arrays nums1 and nums2 of size m and n respectively, return the median of the two sorted arrays. The overall run time complexity should be O(log (m+n)). Examp
Can you solve this real interview question? Median of Two Sorted Arrays - Given two sorted arrays nums1 and nums2 of size m and n respectively, return the median of the two sorted arrays. The overall run time complexity should be O(log (m+n)). Examp
有两个排序的数组nums1和nums2分别为m和n。 找到两个排序数组的中位数。总运行时间复杂度应为O(log(m + n))。 假设nums1和nums2不能都为空。 思路 将两个数组合并然后排序,根据合并后新数组长度来计算中位数 代码实现 class Solution: def findMedianSortedArrays(self, nums1: 'List[int]', nums2: ...
https://leetcode-cn.com/problems/median-of-two-sorted-arrays/solution/4-xun-zhao-liang-ge-you-xu-shu-zu-de-zhong-wei-shu/ class Solution { public double findMedianSortedArrays(int[] nums1, int[] nums2) { int n = nums1.length; ...