dp[i] represents the maximum sum of subarray which ends in nums[i], and dp[i] = Math.max(nums[i], dp[i - 1] + nums[i]). and since we have to include nums[i] due to it’s on the defination of dp[i], and when dp[i
LeetCode - The World's Leading Online Programming Learning Platformleetcode.com/problems/maximum-gcd-sum-of-a-subarray/description/ 简单介绍一下题目大意,更详细的描述可以见链接中的原题描述及样例数据: 给定一个长度为n的正整数数组nums。对于nums的任意一个子数组(连续、非空的一段),定义s为子数组...
dp[i] represents the maximum sum of subarray which ends in nums[i], and dp[i] = Math.max(nums[i], dp[i - 1] + nums[i]). and since we have to include nums[i] due to it’s on the defination of dp[i], and when dp[i-1]<0 we can just choose not to add it. so the...
Maximum Sum Subarray of Size K (easy) 问题描述 解决方法 代码 课后回顾 sliding window pattern 滑窗应用场景 滑动窗口模式(sliding window pattern)是用于在给定数组或链表的特定窗口大小上执行所需的操作,比如寻找包含所有 1 的最长子数组。从第一个元素开始滑动窗口并逐个元素地向右滑,并根据你所求解的问题调整...
1classSolution {2public:3vector<int> maxSumOfThreeSubarrays(vector<int>& nums,intk) {4intn=nums.size();5inttmpmax=-1;6vector<int>sum(n+1,0);7vector<int>leftPos(n,0);8vector<int>rightPos(n,0);9vector<int>res(3,0);10for(inti=1; i<=n; i++) sum[i]=nums[i-1]+sum[...
public int[] maxSumOfThreeSubarrays(int[] nums, int K) { //W is an array of sums of windows int[] W = new int[nums.length - K + 1]; int sum = 0; for (int i = 0; i < nums.length; i++) { sum += nums[i]; ...
Find the contiguous subarray within an array (containing at least one number) which has the largest sum.For example, given the array [-2,1,-3,4,-1,2,1,-5,4],the contiguous subarray [4,-1,2,1] has the largest sum = 6.
Maximum subarray sumGiven an \\\(n imes n\\\) array A of integers, with at least one positive value, the maximum subarray sum problem consists in finding the maximum sum among the sums of all rectangular subarrays of A. The maximum subarray problem appears in several scientific applications...
Leetcode刷题 349.两个数组的交集 Intersection of Two Arrays 06:07 Leetcode刷题 219.存在重复元素 II Contains Duplicate II 04:57 Leetcode刷题 66.加一 Plus one 05:50 Leetcode刷题 53.最大子序和 Maximum Subarray 10:21 Leetcode刷题 62. 不同路径 Unique Paths 09:49 Leetcode刷题 198...
Now to combine two arrays, the maximum subarray sum of the combined array would bemax(p(1)2,p(2)2,p(1)2+p(1)3+p(2)1+p(2)2)max(p2(1),p2(2),p2(1)+p3(1)+p1(2)+p2(2)). The remaining left and right side parts can be maintained easily. ...