https://leetcode.com/problems/maximum-subarray/ 题目描述 Given an integer array nums, find the contiguous subarray (containing at least one number) which has the largest sum and retur
Given an array nums and a target value k, find the maximum length of a subarray that sums to k. If there isn’t one, return 0 instead.Hashmap is also used in this problem. Iterate the array and calc…
Maximum Size Subarray Sum Equals k -- LeetCode Given an arraynumsand a target valuek, find the maximum length of a subarray that sums tok. If there isn't one, return 0 instead. Example 1: Givennums=[1, -1, 5, -2, 3],k=3, return4. (because the subarray[1, -1, 5, -2]su...
此算法和贪心算法有点像,但是又不完全一样:不使用额外的变量来保存 maxSub,而是把 curSum 保存到了当前数字的位置(动规会保存多个临时结果),最后max(所有的curSum)。 Python 代码: ## 用数组本身,来保存结果 class Solution(): ## 动态规划 def maxSubArray(self, nums): for i in range(1, len(nums)...
* @param k: a target value * @return: the maximum length of a subarray that sums to k*/intmaxSubArrayLen(vector<int> &nums,intk) {//Write your code hereunordered_map<int,int>m; m[0] = -1;intres =0;intsum =0;for(inti =0;i < nums.size();i++){ ...
Leetcode刷题 349.两个数组的交集 Intersection of Two Arrays 06:07 Leetcode刷题 219.存在重复元素 II Contains Duplicate II 04:57 Leetcode刷题 66.加一 Plus one 05:50 Leetcode刷题 53.最大子序和 Maximum Subarray 10:21 Leetcode刷题 62. 不同路径 Unique Paths 09:49 Leetcode刷题 198...
and clearly, we need a global variable to keep record of the global maximum. so the code will be: class Solution { public int maxSubArray(int[] nums) { if(nums==null || nums.length == 0) return 0; int[] dp = new int[nums.length]; ...
(vector<int> &a, int l, int r) { if (l == r) { return (Status) {a[l], a[l], a[l], a[l]}; } int m = (l + r) >> 1; Status lSub = get(a, l, m); Status rSub = get(a, m + 1, r); return pushUp(lSub, rSub); } int maxSubArray(vector<int>& nums...
in prefixSum array, find the maxisum size subarray sum equals k// sum of subarray (i, j) = prefixSum [j] - prefixSum[i]Map<Integer,Integer>prefixSumVsIndex=newHashMap<>();prefixSumVsIndex.put(0,-1);intmaxSize=0;intprefixSum=0;for(intj=0;j<nums.length;j++){prefixSum+=nums[...
the contiguous subarray [4,-1,2,1] has the largest sum = 6.中文:主要是给定一个数组,求解数组的子数组中,数组元素和最大的那一个子数组,返回的是最大子数组的和。2. 求解解法一最简单也是最容易想到的思路就是三层循环,对(i,j),i<=j的情况进行遍历,这种情况下的算法复杂度为O($n^3$)。代码如...