LeetCode53 Maximum sum of subarray classic dp: dp[i] represents the maximum sum of subarray which ends in nums[i], and dp[i] = Math.max(nums[i], dp[i - 1] + nums[i]). and since we have to include nums[i] due to it’s on the defination of dp[i], and when dp[i-1]<...
LeetCode - The World's Leading Online Programming Learning Platformleetcode.com/problems/maximum-gcd-sum-of-a-subarray/description/ 简单介绍一下题目大意,更详细的描述可以见链接中的原题描述及样例数据: 给定一个长度为n的正整数数组nums。对于nums的任意一个子数组(连续、非空的一段),定义s为子数组...
LeetCode53 Maximum sum of subarray classic dp: dp[i] represents the maximum sum of subarray which ends in nums[i], and dp[i] = Math.max(nums[i], dp[i - 1] + nums[i]). and since we have to include nums[i] due to it’s on the defination of dp[i], and when dp[i-1]<...
Given an integer array nums and two integers firstLen and secondLen, return the maximum sum of elements in two non-overlapping subarrays with lengths firstLen and secondLen. The array with length firstLen could occur before or after the array with length secondLen, but they have to be non...
1. dp[i] stands for max sum of subarray[0,i] (nums[i] must be used) 2. coz any negative will worsen final result. supposing I am standing at current nums[i], if previous sum dp[i-1] > 0, it will benifit result, then we wrap dp[i-1] + nums[i] to dp[i] ...
Can you solve this real interview question? Maximum Sum of Two Non-Overlapping Subarrays - Given an integer array nums and two integers firstLen and secondLen, return the maximum sum of elements in two non-overlapping subarrays with lengths firstLen and
Given an integer array nums, find the contiguous subarray (containing at least one number) which has the largest sum and return its sum.A subarray is a contiguous part of an array. 英文版地址 leetcode.com/problems/m 中文版描述 给你一个整数数组 nums ,请你找出一个具有最大和的连续子数组(...
题目地址: https://leetcode.com/problems/maximum-sum-of-3-non-overlapping-subarrays/description/ 题目描述: In a given array nums of positive integers, find three non-overlapping subarrays with maximum sum. Each subarray will be of size k, and we want to maximize the sum of all 3*k entri...
Python 代码：这种做法，虽然可以解决短的数列问题，但在提交时会超时。解法二：贪心+滑窗 思路：可以打败90%左右的用户，不过最经典的是分治法。最大子数列题，也是分治算法的经典应用。解法三：动态规划 第一步，定义临时数组，保存每个位置的临时结果。当前位置的最大子序列的和为：max([dp[0], ...
LeetCode刷题日记 Day 28 Part 2 - Maximum Product Subarray, 视频播放量 70、弹幕量 0、点赞数 0、投硬币枚数 0、收藏人数 0、转发人数 0, 视频作者 blackwoodkane, 作者简介 ,相关视频:LeetCode刷题日记 Day 11 Part 2 - Unique Paths,LeetCode刷题日记 Day 24 Part 1