Python代码 classSolution(object):defmaxSubArray(self, nums):""" :type nums: List[int] :rtype: int """ifnotnums:return0dp =0sum= -0xFFFFFFFFforiinrange(len(nums)): dp = nums[i] + (dpifdp >0else0)# if dp > 0: dp = nums[i] + dp, else: dp = nums[i]sum=max(sum, dp...
python代码如下: 1classSolution:2#@param A, a list of integers3#@return an integer4defmaxSubArray(self, A):5#kadane's dynamic programming algorithm6maxSum = -1 * (1 << 30)7currSum =maxSum8forainA:9currSum = max(a, a +currSum)10maxSum =max(maxSum, currSum)11returnmaxSum...
来自专栏 · 刻意练习之LeetCode #53 Maximum Subarray 先尽量正确理解题目: 给定一个整数数列nums, 找到其中具有最大sum的连续子数列片段。 Example: Input: [-2,1,-3,4,-1,2,1,-5,4], Output: 6 Explanation: [4,-1,2,1] has the largest sum = 6. ...
## LeetCode 53 最大子数列和 Maximum Subarray class Solution(): def maxSubArray(self, nums): l = len(nums) dp = [0] * l ## 初始化数组全部为0 ## 套路第三步,初始特殊值为 nums 第一个元素 dp[0] = nums[0] #res_max = dp[0] ## 最终结果也初始化为 nums 第一个元素 for i in...
[Leetcode][python]Maximum Subarray/最大子序和 题目大意 由N 个整数元素组成的一维数组 (A[0], A[1],…,A[n-1], A[n]),这个数组有很多连续子数组,那么其中数组之和的最大值是什么呢? 子数组必须是连续的。 不需要返回子数组的具体位置。
classSolution {public:intmaxSubArrayLen(vector<int>& nums,intk) {if(nums.empty())return0;intres =0; unordered_map<int, vector<int>>m; m[nums[0]].push_back(0); vector<int> sum =nums;for(inti =1; i < nums.size(); ++i) { ...
public int maxSubArrayLen(int[] nums, int k) { Map<Integer, Integer> hm = new HashMap<>(); //use nums[i] as key and its index as value int result = 0, sum = 0; hm.put(0, -1); for(int i = 0; i < nums.length; i++) { ...
Given an integer array nums and two integers firstLen and secondLen, return the maximum sum of elements in two non-overlapping subarrays with lengths firstLen and secondLen. The array with length firstLen could occur before or after the array with length secondLen, but they have to be non...
Can you solve this real interview question? Maximum Sum Circular Subarray - Given a circular integer array nums of length n, return the maximum possible sum of a non-empty subarray of nums. A circular array means the end of the array connects to the beg
For example, given the array[2,3,-2,4], the contiguous subarray[2,3]has the largest product =6. 找出最大连续乘积。 与最大连续和类似,但有不同。 最大值可能是由当前最大正值乘正值,也有可能是由当前最小负值乘负值得到, 如果乘当前值导致绝对值变小,则可以以这个值作为新起点。