Given an array nums and a target value k, find the maximum length of a subarray that sums to k. If there isn’t one, return 0 instead. Hashmap is also used in this problem. Iterate the array and calculate the sum, if map[sum-k] in the hashmap, update the maxlength=max(maxlength...
提到求子数组之和,那么肯定首推卡达内算法 Kadane's Algorithm,在之前的题目Maximum Subarray和Maximum Subarray Sum with One Deletion中也有应用到。但是你以为就是直接将数组重复k次,在新的大数组中直接用 Kadane 算法么,那就 Naive 了,好歹这也是道 Medium 的题目,得尊重一下。看一下数组长度和k值的范围,over...
---> i - map.get(sum - k)在这个例子里就是5-2 代码如下: public int maxSubArrayLen(int[] nums, int k) { int sum = 0, max = 0; HashMap<Integer, Integer> map = new HashMap<Integer, Integer>(); for (int i = 0; i < nums.length; i++) { sum = sum + nums[i]; if ...
Given an arraynumsand a target valuek, find the maximum length of a subarray that sums tok. If there isn't one, return 0 instead. Note: The sum of the entirenumsarray is guaranteed to fit within the 32-bit signed integer range. Example 1: Givennums=[1, -1, 5, -2, 3],k=3, ...
classSolution {public:intmaxSubArrayLen(vector<int>& nums,intk) {if(nums.empty())return0;intres =0; unordered_map<int, vector<int>>m; m[nums[0]].push_back(0); vector<int> sum =nums;for(inti =1; i < nums.size(); ++i) { ...
Given an arraynumsand a target valuek, find the maximum length of a subarray that sums tok. If there isn't one, return 0 instead. Note: The sum of the entirenumsarray is guaranteed to fit within the 32-bit signed integer range. ...
Given an array nums and a target value k, find the maximum length of a subarray that sums to k. If there isn’t one, return 0 instead. this is a really easy undetstanding problem. and the follow up is do it in O(n) time. ...
如果每次得到新的candidate都和全局的maxSum进行比较,那么必然能找到最大的max sum subarray. 在循环过程中,用maxSum记录历史最大的值。从nums[0]到nums[n-1]一步一步地进行。 思路二: 遍历array,对于每一个数字,我们判断,(之前的sum + 这个数字) 和 (这个数字) 比大小,如果(这个数字)自己就比 (之前的su...
思路：使用两层循环，时间复杂度是 O(n^2)。Python 代码：这种做法，虽然可以解决短的数列问题，但在提交时会超时。解法二：贪心+滑窗 思路：可以打败90%左右的用户，不过最经典的是分治法。最大子数列题，也是分治算法的经典应用。解法三：动态规划 第一步，定义临时数组，保存每个位置的临时结果。...
Can you solve this real interview question? Maximum Product Subarray - Given an integer array nums, find a subarray that has the largest product, and return the product. The test cases are generated so that the answer will fit in a 32-bit integer. E