class Solution: def maxSubArray(self, nums: List[int]) -> int: if sum(nums[0:])<=sum(nums[:-1]): return sum( self.maxSubArray(nums[:-1]) ) elif sum(nums[1:])>=sum(nums): return sum(self.maxSubArray(nums[1:])) else: return sum(self.maxSubArray(nums[1:-1])) ...
两层索引的嵌套全循环为 O(n2) ,最内里计算一个sum,为 O(n) ,整体而言就是。 S2:首尾索引全循环,O(n^2) 在上一个Solution中,我们发现在计算其内部的sum时,每次都要重新整体计算该子数列的和,重复部分有大量重复计算,那怎么办? 举个简单的例子: [1,2,3]的和是多少?
Python3解leetcode Maximum Subarray 问题描述: Given an integer arraynums, find the contiguous subarray (containing at least one number) which has the largest sum and return its sum. Example: Input: [-2,1,-3,4,-1,2,1,-5,4], Output: 6 Explanation: [4,-1,2,1] has the largest sum...
class Solution(object): def maxSubArrayHelper(self,nums, l, r): if l > r: return -2147483647 m = (l+r) / 2 leftMax = sumNum = 0 for i in range(m - 1, l - 1, -1): # 从中间向左遍历 sumNum += nums[i] leftMax = max(leftMax, sumNum) rightMax = sumNum = 0 for ...
leetcode 【 Maximum Subarray 】python 实现 题目: Find the contiguous subarray within an array (containing at least one number) which has the largest sum. For example, given the array[−2,1,−3,4,−1,2,1,−5,4], the contiguous subarray[4,−1,2,1]has the largest sum =6....
Python: classSolution:defmaximumSum(self,arr:List[int])->int:zero,one=[arr0]]*(n:=len(arr)),[arr[0]]*nforiinrange(1,n):zero[i],one[i]=max(arr[i],zero[i-1]+arr[i]),max(zero[i-1],one[i-1]+arr[i])((zero),max(one))...
[Leetcode][python]Maximum Subarray/最大子序和 题目大意 由N 个整数元素组成的一维数组 (A[0], A[1],…,A[n-1], A[n]),这个数组有很多连续子数组,那么其中数组之和的最大值是什么呢? 子数组必须是连续的。 不需要返回子数组的具体位置。 数组中包含:正整数,零,负整数。
classSolution{public:intmaxSubarraySumLessOrEqualK(std::vector<int>&nums,inttarget){if(nums.size()==0){return0;}std::vector<int>sumArray;intsum=0;intmaxLen=0;sumArray.push_back(sum);for(intcur=0;cur<nums.size();++cur){sum+=nums[cur];intstart=binarySearch(sumArray,sum-target);int...
Maximum Subarray 参考资料: https://leetcode.com/problems/maximum-subarray-sum-with-one-deletion/ https://leetcode.com/problems/maximum-subarray-sum-with-one-deletion/discuss/377397/Intuitive-Java-Solution-With-Explanation https://leetcode.com/problems/maximum-subarray-sum-with-one-deletion/discuss/37...
Input: nums = [12,17,15,13,10,11,12]Output: 33Explanation: [10,11,12] is the ascending subarray with the maximum sum of 33. Constraints: 1 <= nums.length <= 100 1 <= nums[i] <= 100 Easy 题目; 遍历确认最大值即可; classSolution{public intmaxAscendingSum(int[]nums){int temp=...