问题简介 本文将介绍计算机算法中的经典问题——最大子数组问题(maximum subarray problem)。所谓的最大子数组问题,指的是:给定一个数组A,寻找A的和最大的非空连续子数组。比如,数组 A = [-2, -3, 4, -1, -2…
Kandane's algorithm 原理:令以i位置为末尾的子数组中的最大和子数组为B(i),则B(i+1)=max(A(i+1),A(i+1)+B(i)),其中A(i+1)是i+1处的元素。 依据递推公式我们可以得到以下代码。 def max_subarray(A): max_ending_here = max_so_far = A[0] for x in A[1:]: max_ending_here =...
the minimum subarray problem is to find the contiguous subarray having the smallest sum. Variants of Kadane’s algorithm can solve these problems in O(N) time.
【数据结构】算法 Maximum Subarray 最大子数组:Maximum Subarray 参考来源:Maximum subarray problem Kadane算法扫描一次整个数列的所有数值,在每一个扫描点计算以该点数值为结束点的子数列的最大和(正数和)。该子数列由两部分组成:以前一个位置为结束点的最大子数列、该位置的数值。因为该算法用到了“最佳子结构”...
kadane's algorithm 示例和证明(从5:31左右开始) 假设之前造成最大值的subarray是M,当for loop 开始循环后,每遇到一个值,我们判断是否要取X,即 max_current = max(num,max_current+num) 即当前在index nth时(截止到并包括X),当前造成最大值的subarray=max([X],[M,X]),也就是我们到底要不要之前的M。
本文将介绍计算机算法中的经典问题——最大子数组问题(maximum subarray problem)。所谓的最大子数组问题,指的是:给定一个数组A,寻找A的和最大的非空连续...
is maximum. I would like to find an algorithm with complexity less thanO(n2). For instance, if the array is then the underlined subarray would be the one we are looking for (its "score" is 7×4 = 28) . Notice that if we changed "sum" into "min" the problem would be solvable in...
The Kadane's Algorithm and Divide and Conquer algorithm share a commonality in their utilization, which is the ability to compute the maximum sum of a subarray within an array and determine which subarray holds that maximum sum. To accomplish this, it requires time to traverse the data one by...
53 Maximum Subarray 40.10% 子数组和的最大值 动态规划法Dynamic Programming:时间复杂度为o(n),试想从头遍历这个数组。对于数组中的其中一个元素,它只有两个选择: 1. 要么加入之前的...leetcode 53 Maximum Subarray leetcode 53 Maximum Subarray 给定一个数组(至少包含一个整数),找出一个该数组的连续子数组...
Implement Maximum Subarray Sum Algorithm Original Task Write a function that takes an array of integers and returns the maximum sum of a contiguous subarray, handling both positive and negative numbers. Summary of Changes Implemented Kadane's algorithm to solve the maximum subarray sum problem. The ...