}//对每个节点遍历求左右两个节点的做大加上本身,然后取最大的值就是maximum path sum了intmaxPathSum(TreeNode *root) {if(!root)return0;inttmpl = INT_MIN, tmpr =INT_MIN;intcur =curMax(root);if(root ->left) tmpl= maxPathSum(root ->left);if(root ->right) tmpr= maxPathSum(root ->...
3. R-sub + Node 4. L-sub + Node + R-sub (in here the max value cannot be passed to the parent) publicstaticintmaxPathSum(TreeNode root){int[] max = {Integer.MIN_VALUE};// 因为Java里都是pass by value所以利用数组传!rec(root, max);returnmax[0]; }publicstaticintrec(TreeNode r...
Binary Tree Maximum Path Sum@LeetCode Binary Tree Maximum Path Sum 动态规划+深度优先搜索。把大问题(求整棵树的路径最大值)拆分成小问题(每颗子树的路径最大值),递推公式为:当前树的路径最大值=max(左子树的路径最大值, 右子树的路径最大值)+当前根节点的值。以此来推出最后全树的最大路径值。 实现...
int path_sum = max(singlePathSum(root->left), singlePathSum(root->right)); return max(0, (root->val + path_sum)); } }; 源码分析 注意singlePathSum中最后的返回值,如果其路径长度path_sum比0还小,那么取这一段路径反而会减少最终的路径和,故不应取这一段,我们使用0表示这一隐含意义。 题解...
Leetcode Binary Tree Maximum Path Sum Given a binary tree, find the maximum path sum. The path may start and end at any node in the tree. For example: Given the below binary tree, 1 / \ 2 3 1. 2. 3. Return6. 对于每个结点,我们需要比较三个值。
参考: https://shenjie1993.gitbooks.io/leetcode-python/124%20Binary%20Tree%20Maximum%20Path%20Sum.html 我们现在要求最大路径和,那么就要分别得到左右两条路径的最大和。而左路径的最大和为左节点的值加上它左右路径中较大的路径和,右路径最大和为右节点的值加上它左右路径中较大的路径和。 注意:如果...
[LeetCode][Java] Binary Tree Maximum Path Sum 题目: Given a binary tree, find the maximum path sum. The path may start and end at any node in the tree. For example: Given the below binary tree, AI检测代码解析 1 / \ 2 3 1....
intsum=l+r+root->val; ans=max(ans,sum); returnmax(l,r)+root->val; } }; Related Problems: [解题报告] LeetCode 687. Longest Univalue Path [解题报告] LeetCode 543. Diameter of Binary Tree Published inHardandTree hard path sum ...
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