returnmax(max(rootStartPathMaxSum(root->left)+root->val,rootStartPathMaxSum(root->right)+root->val),root->val); } }; 在小数据集上运行良好,但是一到大数据集就hold不住了,运行结果如下: 其实写的过程就意识到了rootStartPathMaxSum有很多次被重复调用,于是得采用一种自底向上的算法,自己想了半天...
4. L-sub + Node + R-sub (in here the max value cannot be passed to the parent) publicstaticintmaxPathSum(TreeNode root){int[] max = {Integer.MIN_VALUE};// 因为Java里都是pass by value所以利用数组传!rec(root, max);returnmax[0]; }publicstaticintrec(TreeNode root,int[] max){if...
取其4个值中得最大值作为子树的最大路径和。 classSolution {public:intmaxSum =INT_MIN;intgetMaxSum(TreeNode*root){if(root == NULL)return0;intleftSum = getMaxSum(root->left), rightSum = getMaxSum(root->right);intcurSum = max(root->val, max(root->val+leftSum, root->val+rightSum...
self.maxSum = float('-inf') self._maxPathSum(root) return self.maxSum def _maxPathSum(self, root): # DFS if root is None: return 0 left = self._maxPathSum(root.left) right = self._maxPathSum(root.right) left = left if left > 0 else 0 right = right if right > 0 else ...
3,2,4组成的子树是不能作为1的子节点再进行计算的, privateint maxValue=Integer.MIN_VALUE;publicintmaxPathSum(TreeNoderoot){maxPathSumHelper(root);returnmaxValue;}publicintmaxPathSumHelper(TreeNoderoot){if(root==null)return0;//左子节点的值int left=maxPathSumHelper(root.left);//右子节点的值...
LeetCode刷题日记 Day 8 Part 2 - Lowest Common Ancestor of a Binary Search Tree 83 -- 4:22 App LeetCode刷题日记 Day 17 Part 1 - Longest Common Prefix 2 -- 7:37 App LeetCode刷题日记 Day 91 Part 1 - Path with Maximum Probability 88 -- 5:13 App LeetCode刷题日记 Day 14 Part...
http://bangbingsyb.blogspot.com/2014/11/leetcode-binary-tree-maximum-path-sum.html http://www.programcreek.com/2013/02/leetcode-binary-tree-maximum-path-sum-java/ 另外,这道题目的BST条件,似乎没什么用。因为如果全是负数,BST也没帮助了。
Given a non-empty binary tree, find the maximum path sum. For this problem, a path is defined as any sequence of nodes from some starting node to any node in the tree along the parent-child connections. The path must contain at least one node and does not need to go through the root...
leetcode:Binary Tree Maximum Path Sum | LeetCode OJ lintcode:(94) Binary Tree Maximum Path Sum Problem Statement Given a binary tree, find the maximum path sum. The path may start and end at any node in the tree. Example Given the below binary tree: ...
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