returnmax(max(rootStartPathMaxSum(root->left)+root->val,rootStartPathMaxSum(root->right)+root->val),root->val); } }; 在小数据集上运行良好,但是一到大数据集就hold不住了,运行结果如下: 其实写的过程就意识到了rootStartPathMaxSum有很多次被重复调用,于是得采用一种自底向上的算法,自己想了半天...
}//对每个节点遍历求左右两个节点的做大加上本身,然后取最大的值就是maximum path sum了intmaxPathSum(TreeNode *root) {if(!root)return0;inttmpl = INT_MIN, tmpr =INT_MIN;intcur =curMax(root);if(root ->left) tmpl= maxPathSum(root ->left);if(root ->right) tmpr= maxPathSum(root ->...
[LeetCode]Binary Tree Maximum Path Sum Question Given a binary tree, find the maximum path sum. For this problem, a path is defined as any sequence of nodes from some starting node to any node in the tree along the parent-child connections. The path must containat least one nodeand does...
* TreeNode(int x) : val(x), left(NULL), right(NULL) {} * };*/classSolution {intm_sum;public:intdfs(TreeNode *root) {if(root ==NULL)return0;intl = dfs(root->left);intr = dfs(root->right);intsum = root->val;if(l >0) sum+=l;if(r >0) sum+=r;#if0cout<<"l\t"<...
http://bangbingsyb.blogspot.com/2014/11/leetcode-binary-tree-maximum-path-sum.html http://www.programcreek.com/2013/02/leetcode-binary-tree-maximum-path-sum-java/ 另外,这道题目的BST条件,似乎没什么用。因为如果全是负数,BST也没帮助了。
leetcode题目链接 题目描述 Given a binary tree, find the maximum path sum. 给出一棵二叉树,计算其最大路径和。 The path may start and end at any node in the tree. 路径的起止结点必须位于树内。 For example: 例如: Given the below binary tree, ...
LeetCode刷题日记 Day 8 Part 2 - Lowest Common Ancestor of a Binary Search Tree 83 -- 4:22 App LeetCode刷题日记 Day 17 Part 1 - Longest Common Prefix 2 -- 7:37 App LeetCode刷题日记 Day 91 Part 1 - Path with Maximum Probability 88 -- 5:13 App LeetCode刷题日记 Day 14 Part...
1537. 最大得分 - 你有两个 有序 且数组内元素互不相同的数组 nums1 和 nums2 。 一条 合法路径 定义如下: * 选择数组 nums1 或者 nums2 开始遍历(从下标 0 处开始)。 * 从左到右遍历当前数组。 * 如果你遇到了 nums1 和 nums2 中都存在的值,那么你可以切换路径到
Scoreis defined as the sum of uniques values in a valid path. Return the maximumscoreyou can obtain of all possiblevalid paths. Since the answer may be too large, return it modulo 10^9 + 7. Example 1: Input: nums1 = [2,4,5,8,10], nums2 = [4,6,8,9] ...
Can you solve this real interview question? Binary Tree Maximum Path Sum - A path in a binary tree is a sequence of nodes where each pair of adjacent nodes in the sequence has an edge connecting them. A node can only appear in the sequence at most once.