packageleetcode// 解法一 优化版funcmaxOperations(nums[]int,kint)int{counter,res:=make(map[int]int),0for_,n:=rangenums{counter[n]++}if(k&1)==0{res+=counter[k>>1]>>1// 能够由 2 个相同的数构成 k 的组合已经都排除出去了,剩下的一个单独的也
问Java MaxFlow算法，生成边的问题EN贝尔曼-福特算法（Bellman-Ford）是由理查德·贝尔曼（Richard Bellman...
Return a list of two integers: the first integer is the maximum sum of numeric characters you can collect, and the second is the number of such paths that you can take to get that maximum sum, taken modulo10^9 + 7. In case there is no path, return[0, 0]. Example 1: Input: boa...
the first will be the maximum sum we can collect during the path. and the second is the number of path which there sum is the maximum sum, if overflowed, take module 10^9 + 7. if there is no such path, return the result as [0,0] 也就是说 要找最大加和路径和有多少条这样的路径。
分析 主要考察 dp 在二维数据上的迭代 code class Solution(object): def pathsWithMaxScore(self, matrix):ll= len(matrix) dp = [[[0,0] forjin range(ll)]for i in range(ll)]def vp(i,j):if matrix[i][j]in'SE': return0returnord(matrix[i][j])-ord('0')if matrix == ['EX','XS...
https://leetcode.com/problems/max-points-on-a-line/ 题目: Given n points on a 2D plane, find the maximum number of points that lie on the same straight line. 思路: 对所有可以配对的点计算他们之间的斜率,并保存。时间复杂度O(n^2),空间复杂度为O(n)。
maxPathSum https://leetcode.com/problems/binary-tree-maximum-path-sum/ 给定一个二叉树,求一个叶子节点到另外一个叶子节点的最大路径和 image.png int maxDepthRes=Integer.MIN_VALUE;//初始化全局变量,结果为一个最小值publicintmaxPathSum(TreeNoderoot){maxPathSumHelper(root);returnmaxDepthRes;}//...
1129-Shortest-Path-with-Alternating-Colors 1133-Largest-Unique-Number 1134-Armstrong-Number 1135-Connecting-Cities-With-Minimum-Cost 1136-Parallel-Courses 1140-Stone-Game-II .gitignore qrcode.png readme.md Breadcrumbs Play-Leetcode /0485-Max-Consecutive-Ones / cpp-0485/ ...
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[leetcode] Min/Max Cost to Reach A Target 本文题目: 746. 使用最小花费爬楼梯:见文章。 221. 最大正方形:见文章。 322. 零钱兑换 983. 最低票价 650. 只有两个键的键盘 279. 完全平方数 474. 一和零 「最小路径和」系列题目(经典且简单):...