Return a list of two integers: the first integer is the maximum sum of numeric characters you can collect, and the second is the number of such paths that you can take to get that maximum sum, taken modulo10^9 + 7. In case there is no path, return[0, 0]. Example 1: Input: boa...
packageleetcode// 解法一 优化版funcmaxOperations(nums[]int,kint)int{counter,res:=make(map[int]int),0for_,n:=rangenums{counter[n]++}if(k&1)==0{res+=counter[k>>1]>>1// 能够由 2 个相同的数构成 k 的组合已经都排除出去了,剩下的一个单独的也不能组成 k 了// 所以这里要把它的频次...
Return a list of two integers: the first integer is the maximum sum of numeric characters you can collect, and the second is the number of such paths that you can take to get that maximum sum, taken modulo 10^9 + 7. In case there is no path, return [0, 0]. Example 1: Input: ...
1129-Shortest-Path-with-Alternating-Colors 1133-Largest-Unique-Number 1134-Armstrong-Number 1135-Connecting-Cities-With-Minimum-Cost 1136-Parallel-Courses 1140-Stone-Game-II .gitignore qrcode.png readme.md Breadcrumbs Play-Leetcode /0485-Max-Consecutive-Ones / cpp-0485/ ...
代码运行次数:0 运行 AI代码解释 from pyquboimportArray,Binaryimportnetworkxasnximportitertoolsimportneal defrandom_graph(node_num,p=0.3):G=nx.Graph()H=nx.path_graph(node_num)G.add_nodes_from(H)comb=list(itertools.combinations(range(node_num),2))foreincomb:probability=random.random()#生成随机...
小红书 max average leetcode 649 貌似 头条 max point line 寻找1000000w以内素数 阿里巴巴 path sum ii 踏马问题 某个创业公司 完全二叉树的节点个数_牛客网_牛客在手,offer不愁
maxPathSum https://leetcode.com/problems/binary-tree-maximum-path-sum/ 给定一个二叉树,求一个叶子节点到另外一个叶子节点的最大路径和 image.png int maxDepthRes=Integer.MIN_VALUE;//初始化全局变量,结果为一个最小值publicintmaxPathSum(TreeNoderoot){maxPathSumHelper(root);returnmaxDepthRes;}//...
Code This branch is up to date with kdn251/interviews:master. Latest commit Git stats 445 commits Files Failed to load latest commit information. Type Name Latest commit message Commit time company cracking-the-coding-interview images leetcode uva .DS_Store .gitignore .project ...
the first will be the maximum sum we can collect during the path. and the second is the number of path which there sum is the maximum sum, if overflowed, take module 10^9 + 7. if there is no such path, return the result as [0,0] ...
分析 主要考察 dp 在二维数据上的迭代 code class Solution(object): def pathsWithMaxScore(self, matrix):ll= len(matrix) dp = [[[0,0] forjin range(ll)]for i in range(ll)]def vp(i,j):if matrix[i][j]in'SE': return0returnord(matrix[i][j])-ord('0')if matrix == ['EX','XS...