1classSolution2{3public:4intmaxSumCycle(vector<int>&vec,int&left,int&right)5{6intmaxsum = INT_MIN, curMaxSum =0;7intminsum = INT_MAX, curMinSum =0;8intsum =0;9intbegin_max =0, begin_min =0;10intminLeft, minRight;11for(inti =0; i < vec.size(); i++)12{13sum +=vec...
Given a circular array C of integers represented by A, find the maximum possible sum of a non-empty subarray of C. Here, a circular array means the end of the array connects to the beginning of the array. (Formally, C[i] = A[i] when 0 <= i < A.length, and C[i+A.length] ...
public int maxSubarraySumCircular(int[] A) { int[] left = new int[A.length]; int sum = 0, maxsum = 0; for(int i = 0; i < A.length; ++i) { if(i == 0) { left[i] = sum = maxsum = A[i]; } else { sum = Math.max(sum+A[i], A[i]); maxsum = Math.max(max...
Given a circular array C of integers represented by A, find the maximum possible sum of a non-empty subarray of C. Here, a circular array means the end of the array connects to the beginning of the array. (Formally, C[i] = A[i] when 0 <= i < A.length, and C[i+A.length] ...
Input:[-2,-3,-1]Output:-1Explanation:Subarray [-1] has maximum sum -1 Note: -30000 <= A[i] <= 30000 1 <= A.length <= 30000 这道题比较好理解,关于最大子数组的解法 可以参考 Loading...leetcode.com/problems/maximum-subarray/ ...
My Leetcode Solutions. Contribute to developer-kush/Leetcode development by creating an account on GitHub.
My Solutions to Leetcode problems. All solutions support C++ language, some support Java and Python. Multiple solutions will be given by most problems. Enjoy:) 我的Leetcode解答。所有的问题都支持C++语言,一部分问题支持Java语言。近乎所有问题都会提供多个算
class Solution { // max(最大子数组和,数组总和-最小子数组和) public int maxSubarraySumCircular(int[] q) { int n = q.length; if (n == 1) return q[0]; int[] f = new int[n]; int max = q[0], sum = q[0]; for (int i = 1; i < n; i++) { f[i] = Math.max(...
1453. 圆形靶内的最大飞镖数量 - Alice 向一面非常大的墙上掷出 n 支飞镖。给你一个数组 darts ,其中 darts[i] = [xi, yi] 表示 Alice 掷出的第 i 支飞镖落在墙上的位置。 Bob 知道墙上所有 n 支飞镖的位置。他想要往墙上放置一个半径为 r 的圆形靶。使 Alice 掷出的飞镖
唯一的corner case是如果整个数组都是由负数组成的,那么整个数组的和sum跟数组连续的,最小的子数组的和是一样的。最后比较的时候,需要看看到底是case 1的结果更大,还是case 2里面的min subarray更小。 时间O(n) 空间O(1) Java实现 1classSolution {2publicintmaxSubarraySumCircular(int[] A) {3inttotal =...