class Solution: def maximumSubarraySum(self, nums: List[int], k: int) -> int: # ans 维护所有长度为 k 且数字各不相同的子数组中,子数组和的最大值 ans: int = 0 # sum 维护当前滑动窗口 [l, r] 内的数字和 sum: int = 0 # num_to_cnt 表示滑动窗口 [l, r] 内每个数字的出现次数 nu...
1)和maxSum( 2)两种情况; 当sum > 0 时, 有 maxSum(2) + (k-2)*sum. Java代码classSolution{publicintkConcatenationMaxSum(int[] arr,intk){if( arr.length ==0|| arr ==null)return0;if(k <3)return(int) (maxSum(arr, k)%(1e9+7));longsum =0;for(intnum:arr) sum += num;lon...
max_sub_arr_sum=max(max_sub_arr_sum,amount) res= max(res,max_sub_arr_sum + left_max[-1])ifk > 2: res= max(res,max_sub_arr_sum + left_max[-1] + (k-2)*total_sum)returnres % (10 ** 9 + 7)
For example, if arr = [1, 2] and k = 3 then the modified array will be [1, 2, 1, 2, 1, 2]. Return the maximum sub-array sum in the modified array. Note that the length of the sub-array can be 0 and its sum in that case is 0. As the answer can be very large, retu...
Maximum Subarray Sum with One Deletion 参考资料: https://leetcode.com/problems/k-concatenation-maximum-sum/ https://leetcode.com/problems/k-concatenation-maximum-sum/discuss/382885/Short-and-concise-O(N)-C%2B%2B-solution https://leetcode.com/problems/k-concatenation-maximum-sum/discuss/382350/...
2178. 拆分成最多数目的正偶数之和 - 给你一个整数 finalSum 。请你将它拆分成若干个 互不相同 的正偶数之和,且拆分出来的正偶数数目 最多 。 * 比方说,给你 finalSum = 12 ,那么这些拆分是 符合要求 的(互不相同的正偶数且和为 finalSum):(2 + 10) ,(2 + 4 + 6)
LeetCode 325. Maximum Size Subarray Sum Equals k 若谷 追求卓越,成功就会在不经意间追上你 来自专栏 · 今日事 题目: Given an array nums and a target value k, find the maximum length of a subarray that sums to k. If there isn't one, return 0 instead. Note:The sum of the entire nums...
1691. 堆叠长方体的最大高度排序加最长递增子序列 本
1191 K-Concatenation Maximum Sum K 次串联后最大子数组之和 Description: Given an integer array arr and an integer k, modify the array by repeating it k times. For example, if arr = [1, 2] and k = 3 then the modified array will be [1, 2, 1, 2, 1, 2]. ...
1186 Maximum Subarray Sum with One Deletion 删除一次得到子数组最大和 Description: Given an array of integers, return the maximum sum for a non-empty subarray (contiguous elements) with at most one element deletion. In other words, you want to choose a subarray and optionally delete one element...