package leetcode import "math" func maxSubarraySumCircular(nums []int) int { var max1, max2, sum int // case: no circulation max1 = int(math.Inf(-1)) l := len(nums) for i := 0; i < l; i++ { sum += nums[i] if sum > max1 { max1 = sum } if sum < 1 { sum ...
Given a circular array C of integers represented by A, find the maximum possible sum of a non-empty subarray of C. Here, a circular array means the end of the array connects to the beginning of the array. (Formally, C[i] = A[i] when 0 <= i < A.length, and C[i+A.length] ...
1classSolution2{3public:4intmaxSumCycle(vector<int>&vec,int&left,int&right)5{6intmaxsum = INT_MIN, curMaxSum =0;7intminsum = INT_MAX, curMinSum =0;8intsum =0;9intbegin_max =0, begin_min =0;10intminLeft, minRight;11for(inti =0; i < vec.size(); i++)12{13sum +=vec...
int maxSubarraySumCircular(vector<int>& A) { vector<int> pre_sum; int sum = 0; int max_nor= maxSubArray(A); for(int i = A.size()-1; i>=0;i--){ sum += A[i] ; A[i] = -A[i]; } int max_cir = sum + maxSubArray(A); if(sum!=0&& max_cir == 0 ) return max_...
Can you solve this real interview question? Maximum Sum Circular Subarray - Given a circular integer array nums of length n, return the maximum possible sum of a non-empty subarray of nums. A circular array means the end of the array connects to the beg
Given a circular array C of integers represented by A, find the maximum possible sum of a non-empty subarray of C. Here, a circular array means the end of the array connects to the beginning of the array. (Formally, C[i] = A[i] when 0 <= i < A.length, and C[i+A.length] ...
total+=num; }returnmax > 0 ? Math.max(total -min, max) : max; } } 1. 2. 3. 4. 5. 6. 7. 8. 9. 10. 11. 12. 13. lee哥真乃人中龙凤 https://leetcode.com/problems/maximum-sum-circular-subarray/discuss/178422/One-Pass...
LeetCode 325. Maximum Size Subarray Sum Equals k 若谷 追求卓越,成功就会在不经意间追上你 来自专栏 · 今日事 题目: Given an array nums and a target value k, find the maximum length of a subarray that sums to k. If there isn't one, return 0 instead. Note:The sum of the entire nums...
classSolution {public:intmaxSubArrayLen(vector<int>& nums,intk) {intsum =0, res =0; unordered_map<int,int>m;for(inti =0; i < nums.size(); ++i) { sum+=nums[i];if(sum == k) res = i +1;elseif(m.count(sum - k)) res = max(res, i - m[sum -k]);if(!m.count(sum...
public int maxSubArrayLen(int[] nums, int k) { Map<Integer, Integer> hm = new HashMap<>(); //use nums[i] as key and its index as value int result = 0, sum = 0; hm.put(0, -1); for(int i = 0; i < nums.length; i++) { ...