leetcode 363. Max Sum of Rectangle No Larger Than K 写在前面 这题被标记为hard,第一眼看到,确实很容易想到是dp,但思路之后就陷入混乱,原因就是不知道dp的状态转移方程,以及dp过程的开始和结束,本题事实上是两道题目的组合,分别是 Max Sum of Rectangle in a matrix,这道题的题解可以看这个视频(需要翻...
这个问题是这样的(https://leetcode.com/problems/maximum-subarray/): Given an integer array nums, find the contiguous subarray (containing at least one number) which has the largest sum and return its sum. 就是给一组整数,找到一组连续的子序列,让子序列的和最大,并且返回最大和。 比如说: 输入...
Maximum Size Subarray Sum Equals k 参考资料: https://leetcode.com/problems/max-sum-of-rectangle-no-larger-than-k/ https://leetcode.com/problems/max-sum-of-rectangle-no-larger-than-k/discuss/83618/2-Accepted-Java-Solution https://leetcode.com/problems/max-sum-of-rectangle-no-larger-than-...
一、最大连续子序列和 https://leetcode.com/problems/maximum-subarray/description/ https://www.geeksforgeeks.org/largest-sum-contiguous-subarray/ The core ideas are the same: currentMax = max(nums[i], some_operation(currentMax, nums[i])). For each element, we have 2 options: put it insi...
Day4 Maximum Subarray LeetCode53.Maximum Subarray Find the contiguous subarray within an array (containing at least one number) which has the largest sum. For example, given the array [-2,1,-3,4,-1,2,1,-5,4], the contiguou......
0152-Maximum-Product-Subarray 0153-Find-Minimum-in-Rotated-Sorted-Array 0155-Min-Stack 0159-Longest-Substring-with-At-Most-Two-Distinct-Characters 0160-Intersection-of-Two-Linked-Lists 0161-One-Edit-Distance 0167-Two-Sum-II-Input-array-is-sorted 0169-Majority-Element 01...
count(distinct(CountryCode)) 232 是不是看到數字瞬間變小許多了呢?這是因為 DISTINCT() 函式不會計算重複的值。 SUM 我覺得 SUM 得跟 COUNT 放在一起講,我當初剛寫的時候很常把這兩個指令搞混: SUM() 是全部資料的『值』加總 COUNT() 是計算查找欄位總共有多少『筆』資料 ...
same asLeetcode: Number of Submatrices That Sum to Target 1publicclassSolution {2publicintmaxSumSubmatrix(int[][] matrix,intk) {3if(matrix==null|| matrix.length==0 || matrix[0].length==0)returnInteger.MIN_VALUE;4intres =Integer.MIN_VALUE;56introw =matrix.length;7intcol = matrix[0]....
//https://leetcode.com/problems/split-array-largest-sum/description/ public int splitArray(int[] nums, int m) { int start = 0; int end = 0;for (int i = 0; i < nums.length; i++) { start = Math.max(start, nums[i]); // in the end of the loop this will contain the m...
package max_subarrayy; import java.lang.Math; public class max_subarrayy { private static int[] array; public static class mark{ private int lom = 100; private int him; private int value; public mark(int a,int b,int c){ lom = a;him = b;value = c; ...