https://github.com/grandyang/leetcode/issues/644 类似题目: Maximum Average Subarray I 参考资料: https://leetcode.com/problems/maximum-average-subarray-ii/ https://leetcode.com/problems/maximum-average-subarray-ii/discuss/105498/c-binary-search-130ms https://leetcode.com/problems/maximum-average-...
Given an array consisting ofnintegers, find the contiguous subarray of given lengthkthat has the maximum average value. And you need to output the maximum average value. Example 1: Input: [1,12,-5,-6,50,3], k = 4 Output: 12.75 Explanation: Maximum average is (12-5-6+50)/4 = 51...
Can you solve this real interview question? Maximum Average Subarray I - You are given an integer array nums consisting of n elements, and an integer k. Find a contiguous subarray whose length is equal to k that has the maximum average value and return
Given an array consisting ofnintegers, find the contiguous subarray of given lengthkthat has the maximum average value. And you need to output the maximum average value. Example 1: Input: [1,12,-5,-6,50,3], k = 4 Output: 12.75 Explanation: Maximum average is (12-5-6+50)/4 = 51...
【Leetcode_easy】643. Maximum Average Subarray I problem 643. Maximum Average Subarray I 题意:一定长度的子数组的最大平均值。 solution1:计算子数组之后的常用方法是建立累加数组,然后再计算任意一定长度的子数组之和,迭代更新得到最大值。
## LeetCode 53 最大子数列和 Maximum Subarray class Solution(): def maxSubArray(self, nums): l = len(nums) dp = [0] * l ## 初始化数组全部为0 ## 套路第三步,初始特殊值为 nums 第一个元素 dp[0] = nums[0] #res_max = dp[0] ## 最终结果也初始化为 nums 第一个元素 for i in...
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A subarray is a contiguous part of an array. 英文版地址 leetcode.com/problems/m 中文版描述 给你一个整数数组 nums ,请你找出一个具有最大和的连续子数组(子数组最少包含一个元素),返回其最大和。子数组 是数组中的一个连续部分。示例1:输入:nums = [-2,1,-3,4,-1,2,1,-5,4]输出:6解释:...
Can you solve this real interview question? Maximum Product Subarray - Given an integer array nums, find a subarray that has the largest product, and return the product. The test cases are generated so that the answer will fit in a 32-bit integer. E
Ref:https://leetcode-cn.com/problems/maximum-average-subarray-i/ 这道题思路比较清晰,滑动窗口,维持窗口的sum,每次减去滑动前第一个元素,加上滑动后最后一个元素,代码实现如下: classSolution:deffindMaxAverage(self,nums:List[int],k:int)->float:m_sum=sum(nums[:k])result=m_sumfori,jinzip(nums[...