M = max(A) returns the maximum elements of an array. If A is a vector, then max(A) returns the maximum of A. If A is a matrix, then max(A) is a row vector containing the maximum value of each column of A. If A is a multidimensional array, then max(A) operates along the ...
[minA,maxA] = bounds(A) returns the minimum value minA and maximum value maxA in an array. minA is equivalent to min(A) and maxA is equivalent to max(A). example [minA,maxA] = bounds(A,"all") computes the minimum and maximum values over all elements of A. example [minA,maxA] =...
MATLAB Online에서 열기 I have an array that is filled with numbers like a = [0.007 0.008 0.009] In the workspace the value of a is 1x68 double. I tried max(a) :"Subscript indices must either be real positive integers or logicals." ...
fprintf('value of a: %d \n', a); end 1. 2. 3. 输出结果为: value of a: 10 value of a: 11 value of a: 12 value of a: 13 value of a: 14 value of a: 15 value of a: 16 value of a: 17 value of a: 18 value of a: 19 value of a: 20 1. 2. 3. 4. 5. 6. ...
Suppose I have an array of numbers. I want to find all the numbers, and their indices, which are largest then all previous ones. For example, for the array: X = [ 1 2 5 3 4 7 2 3 10 3] I will get: Largest: [1 2 5 7 10] ...
% 'mean'|'median'|'max'|'min' % (Optional) Specifies what value to return for 'funcVal'. % Default is the center of the CI inteval. % % For each cell array inside 'dists' the syntax is: % {'DistributionType',param_1,...,paramN[,'truncate',lowerBound,upperBound]} % where ...
Minimum min Returns the smallest element or elements of an array Maximum max Returns the largest element or elements of an array For more information, see Specify Data Size by Using Expressions and Derive Data Types from Other Data Objects.See...
(dark_I,'dark_I.jpg');Max_dark_channel=double(max(max(dark_I))) %天空亮度dark_channel=double(0.9*dark_I);%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%非局部均值...
qMax=max(q,[],2); q(state,x1)= R(state,x1)+gamma*qMax(x1); % get max of all actions % break if convergence: small deviation on q for 1000 consecutive if sum(sum(abs(q1-q)))<0.0001 & sum(sum(q >0)) if count>1000, episode % report last episode break % for else count=...
% 把输出居中 n = 135; g_t_out_shifted = circshift(g_t_out/max(abs(g_t_out)), n); ...