MATLAB Online에서 열기 A = rand(x, y, z); [maxValue, maxIndex] = max(A(:)); [ix, iy, iz] = ind2sub([x, y, z], maxIndex); [EDITED] Here "A" was created only as test data only. If you have the array already, you need thesize()command to obtain the dimensions...
so I want to find the max angle of u 댓글 수: 0 댓글을 달려면 로그인하십시오. 답변 (1개) Matt J2023년 4월 27일 0 링크 번역 MATLAB Online에서 열기 f=@(u) -( cos(n).*sin(u)+si...
在使用MATLAB时，[m n]=find(a==max)命令用于查找矩阵a中等于max的元素的位置。首先需要确保矩阵a存在。例如：>>a = rand(1,10);这行代码创建了一个1x10的随机数矩阵a。接下来可以使用max函数获取矩阵中的最大值：>>b = max(a);这行代码将矩阵a中的最大值赋给变量b。然后使用find函数查...
matlab中的max/min函数求矩阵的最大值和最小值求矩阵A的最大值的函数有3种调用格式,分别是: (1)max(A):返回一个行向量,向量的第i个元素是矩阵A的第i列上的最大值。 (2...;dim取2时,该函数返回一个列向量,其第i个元素是A矩阵的第i行上的最大值。 求最小值的函数是min,其用法和max完全相同。 ...
In C++, the Standard Template Library (STL) provides powerful algorithms that simplify common tasks. One such task is finding the maximum value in an array. Let’s see how we can use thestd::max_elementalgorithm, a part of the STL, to efficiently locate the maximum value within an array...
[minval,minindex] = min(meandata(N4index:P6index)); Where meandata is a vector representing ...
function y=findmax(A)y=max(A);以上语句保存为m文件 在命令窗口输入：findmax([1,2,3,4,2])
百度试题 结果1 题目找到A矩阵最大元素所在位置的正确Matlab代码是( )。 A. [s,t]=find(A) B. [s,t]=find(max(A)) C. [s,t]=find(A==max(max(A))) D. [s,t]=find(max(max(A))) 相关知识点: 试题来源: 解析 C 反馈 收藏 ...
maxValue = max([Struct.yourData]) % No (:) needed. And save the max value for use in subsequent code. Sign in to comment. Peter O on 5 May 2020 Vote 0 Link Edited: Peter O on 5 May 2020 Open in MATLAB Online If I'm understanding correctly, you have a struct array, s...
Are you sure? It's not what you asked for. You didn't say that you wanted an array of maxes and an array of mins after the individual arrays were all lined up in the upper left corner. And the values will depend on where you align the smaller matrices over the larger mat...