MATLAB Online에서 열기 테마복사 A = rand(x, y, z); [maxValue, maxIndex] = max(A(:)); [ix, iy, iz] = ind2sub([x, y, z], maxIndex); [EDITED] Here "A" was created only as test data only. If you have the
MATLAB Online에서 열기 Hi there, I have a 3 elements cell array: A{1} = @(y) {1*y}; A{2} = @(y) {2*y}; A{3} = @(y) {3*y}; And I want to create a function that will output the maximum value of all 3 elements of A. The below is not working for y...
在使用MATLAB时，[m n]=find(a==max)命令用于查找矩阵a中等于max的元素的位置。首先需要确保矩阵a存在。例如：>>a = rand(1,10);这行代码创建了一个1x10的随机数矩阵a。接下来可以使用max函数获取矩阵中的最大值：>>b = max(a);这行代码将矩阵a中的最大值赋给变量b。然后使用find函数查...
This MATLAB function returns a vector with the local maxima (peaks) of the input signal vector, y.
Now, I am trying to find the first instance the value of maximum comes in the "arr" Array. I have tried the following: 1. ThemeCopy for v=1:x if(maximum==arr(v)) % x=find(arr==maximum); u=u+1; if(u==1) %making sure only the first max value is taken q=value(v); ...
I need to obtain a cell array, "Min", whose cells are vectors with the indexes of the minimum values of B and another cell array, "Max", with the maximum values. The position in each cell array is indicated by the value of A. ...
[minval,minindex] = min(meandata(N4index:P6index)); Where meandata is a vector representing ...
matlab max/min函数用法 matlab中的max/min函数求矩阵的最大值和最小值求矩阵A的最大值的函数有3种调用格式,分别是: (1)max(A):返回一个行向量,向量的第i个元素是矩阵A的第i列上的最大值。 (2...;dim取2时,该函数返回一个列向量,其第i个元素是A矩阵的第i行上的最大值。 求最小值的函数是min,...
Output array, returned as a scalar, vector, matrix, or multidimensional array.maxkreturns thekelements in order from largest to smallest. The order of the elements inBpreserves the order of any equal elements inA. Index array, returned as a vector, matrix, or multidimensional array.Iis the ...
In C++, the Standard Template Library (STL) provides powerful algorithms that simplify common tasks. One such task is finding the maximum value in an array. Let’s see how we can use thestd::max_elementalgorithm, a part of the STL, to efficiently locate the maximum value within an array...