【leetcode】169. 多数元素(majority-element)(模拟)[简单] 链接https://leetcode-cn.com/problems/majority-element/ 耗时 解题:3 min 题解:4 min 题意 给定一个大小为 n 的数组,找到其中的多数元素。多数元素是指在数组中出现次数大于 ⌊ n/2 ⌋ 的元素。 你可以假设数组是非空的
System.out.println("majorityElement---输入:"+ Arrays.toString(arg) +" , 输出:"+ result +" , 用时:"+ ((end - start) /1000) +"微秒");int[] arg2 = {3,2,3,1,2,3,2,3};longstart2 = System.nanoTime();intresult2 = instance.majorityElement2(arg2);longend2 = System.nanoTime...
Majority Element II 题目描述:找出数组中超过向下取整n//3的数 题目链接:Leetcode 229. Majority Element II 题目思路:跟之前n//2的众数不一样的是这里不保证有众数而且可能为空。 还是使用投票法,但是这个要投出2个数字出来,最多,最少0个。所以设置两个计数器。 c1、c2候选者和cnt1、cnt2计数器,当其中...
LeetCode笔记:169. Majority Element Given an array of size n, find the majority element. The majority element is the element that appears more than ⌊ n/2 ⌋ times. You may assume that the array is non-empty and the majority element always exist in the array. 大意: 给出一个尺寸为n...
题目: Given an array of sizen, find the majority element. The majority element is the element that appears more than⌊ n/2 ⌋times. You may assume that the array is non-empty and the majority element always exist in the array. ...
LeetCode[169] Majority Element Given an array of size n, find the majority element. The majority element is the element that appears more than ⌊ n/2 ⌋ times. You may assume that the array is non-empty and the majority element always exist in the array. ...
leetcode 169 Majority Element 题目详情 Given an array of size n, find the majority element. The majority element is the element that appears more than ⌊ n/2 ⌋ times.You may assume that the array is non-empty and the majority element always exist in the array....
【leetcode Java】Majority Element 题目如下 Given an array of sizen, find the majority element. The majority element is the element that appears more than⌊ n/2 ⌋times. You may assume that the array is non-empty and the majority element always exist in the array....
【LeetCode题解】169_求众数(Majority-Element) 目录169_求众数(Majority-Element) 描述 解法一:暴力法 思路 Java 实现 Python 实现 复杂度分析 解法二:哈希表 思路 Java 实现 Python 实现 复杂度分析 解法三:排序 Java 实现 Python 实现 复杂度分析 解法四:随机选择【待完成】 思路 Java实现 Python 实现 ...
The majority element is the element that appears more than ⌊ n/2 ⌋ times. You may assume that the array is non-empty and the majority element always exist in the array. 方法一: 采用所谓的Moore voting algorithm: 每找出两个不同的element,就成对删除即count–,最终剩下的一定就是所求的...