publicclassSolution {publicList<Integer> majorityElement(int[] nums) { List<Integer> list =newArrayList<Integer>();if(nums ==null|| nums.length == 0)returnlist;intn =nums.length;intcount = n/3;intnum1 = nums[0];
Majority Element II Given an integer array of sizen, find all elements that appear more than⌊ n/3 ⌋times. The algorithm should run in linear time and in O(1) space. 方法很笨,其实时间复杂度差不多是O(n²)。 packageleetcode;importjava.util.ArrayList;importjava.util.HashSet;importja...
Majority Element II 题目描述:找出数组中超过向下取整n//3的数 题目链接:Leetcode 229. Majority Element II 题目思路:跟之前n//2的众数不一样的是这里不保证有众数而且可能为空。 还是使用投票法,但是这个要投出2个数字出来,最多,最少0个。所以设置两个计数器。 c1、c2候选者和cnt1、cnt2计数器,当其中...
文章目录 169_求众数(Majority-Element) 描述 解法一:暴力法 思路 Java 实现 Python 实现 复杂度分析 解法二:哈希表 思路 Java 实现 Python 实现 复杂度分析 解法三:排序 Java 实现 Python 实现 复杂度分...Leetcode之Majority Element 问题 问题描述: Given an array of size n, find the majority element...
多数元素(majority-element)(模拟)[简单] 链接https://leetcode-cn.com/problems/majority-element/ 耗时 解题:3 min 题解:4 min 题意 给定一个大小为 n 的数组,找到其中的多数元素。多数元素是指在数组中出现次数大于 ⌊ n/2 ⌋ 的元素。 你可以假设数组是非空的,并且给定的数组总是存在多数元素。
The majority element is the element that appears more than ⌊ n/2 ⌋ times. You may assume that the array is non-empty and the majority element always exist in the array. 方法一: 采用所谓的Moore voting algorithm: 每找出两个不同的element,就成对删除即count–,最终剩下的一定就是所求的...
https://leetcode.com/problems/majority-element-ii/discuss/63584/Concise-JAVA-solution-based-on-Moore's-Voting-Algorithm 还是boyer-moore投票法,这次要的是大于1/3,说明最多有两个candidate,initialize两个candidate,和1/2一样相等就++,小于等于0就换,不一样就--。
Given an array of size n, find the majority element. The majority element is the element that appears more than ⌊ n/2 ⌋ times. You may assume that the array is non-empty and the majority element always exist in the array.
代码(Java): 代码语言:javascript 代码运行次数:0 publicclassSolution{publicintmajorityElement(int[]nums){Arrays.sort(nums);// 先排序returnnums[nums.length/2];// 出现次数超过n/2次的元素排序后一定会出现在中间}} 他山之石: 现在让我们看看Discuss最hot的答案,我的做法并不是最快的,因为排序需要时间,...
Given an array of size n, find the majority element. The majority element is the element that appears more than ⌊ n/2 ⌋ times.You may assume that the array is non-empty and the majority element always exist in the array.