classSolution{publicintmajorityElement(int[] nums){intmajorityCount=nums.length /2;for(intnum1 : nums) {intcount=0;for(intnum2 : nums) {if(num2 == num1) { ++count; } }if(count > majorityCount) {returnnum1; } }thrownewIllegalArgumentException("The array does not contain a majority...
Given an array of sizen, find the majority element. The majority element is the element that appears more than⌊ n/2 ⌋times. You may assume that the array is non-empty and the majority element always exist in the array. 方法1,采用一个map,存储每一个变量的数量,最后得出个数大于n/2...
因为每一对不一样的数都会互相消去,最后留下来的candidate就是众数。 【代码】 public class Solution { public int majorityElement(int[] nums) { //require int size=nums.length; int candidate=nums[0],cnt=1; //invariant for(int i=1;i<size;i++){ int n=nums[i]; if(n==c...
Given an array of size n, find the majority element. The majority element is the element that appears more than ⌊ n/2 ⌋ times. You may assume that the array is non-empty and the majority element always exist in the array. 就是使用HashMap直接计数。 代码如下: import java.util.Hash...
原帖连接:https://leetcode.com/discuss/19151/solution-computation-space-problem-can-extended-situation http://m.blog.csdn.net/blog/wenyusuran/40780253 解决方案: 代码语言:javascript 代码运行次数:0 运行 AI代码解释 classSolution{public:intmajorityElement(vector<int>&nums){int size=nums.size();int vot...
1 31 11 C++ 智能模式 1 2 3 4 5 6 class Solution { public: vector<int> majorityElement(vector<int>& nums) { } }; 已存储 行1,列 1 运行和提交代码需要登录 Case 1Case 2Case 3 nums = [3,2,3] 1 2 3 [3,2,3] [1] [1,2] Source ...
classSolution:defmajorityElement(self,nums):returncollections.Counter(nums).most_common(1)[0][0] 排序 时间:O(nlogn) 空间:O(nlogn) 如果自己编写堆排序,则只需要使用O(1)的额外空间 classSolution{publicintmajorityElement(int[]nums){Arrays.sort(nums);returnnums[nums.length/2];}} ...
这道题出现在了王道的《2019数据结构考研复习指导》的18页,LeetCode中也有这道题。题目大意是:给定一个长度为n的数组,我们定义"主元素"为数组中出现次数超过⌊n/2⌋的元素。 Description Given an array of size n, find the majority element. The majority element is the element that appears more than...
https://leetcode.com/problems/majority-element-ii/ 求大多数的升级版,给定一个int数组,长度为n,找出长度超过n/3的所有int 题目要求只能用O(1)的存储空间,所以排除HashMap的方法目前只能摩尔投票法则 长度超过n/3的所有数字,最多存在两个 类比找n/2的方法,所以假设有两个int, ...
intmajorityElement(vector<int> &num) { intn = num.size(); sort(num.begin(),num.end()); returnnum[n/2]; } }; public class Solution { public int MajorityElement(int[] nums) { Array.Sort(nums); return nums[nums.Length/2]; ...