System.out.println("majorityElement---输入:"+ Arrays.toString(arg) +" , 输出:"+ result +" , 用时:"+ ((end - start) /1000) +"微秒");int[] arg2 = {3,2,3,1,2,3,2,3};longstart2 = System.nanoTime();intresult2 = instance.majorityElement2(arg2);longend2 = System.nanoTime...
题目地址: https://oj.leetcode.com/problems/majority-element/ 题目内容: Given an array of sizen, find the majority element. The majority element is the element that appears more than⌊ n/2 ⌋times. You may assume that the array is non-empty and the majority element always exist in th...
Description Given an array of size n, find the majority element. The majority element is the element that appears more than ⌊ n/2 ⌋ times. You may assume that the array is non-empty and the majority element always exist in the array. Example 1: Input:[3,2,3]Output:3 Example 2...
Given an array of sizen, find the majority element. The majority element is the element that appears more than⌊ n/2 ⌋times. You may assume that the array is non-empty and the majority element always exist in the array. 第一中方案如下:比较通用的一种解法,也比较笨 public class Soluti...
169.Majority Element 这是leetCode第169题 题目 Given an array of size n, find the majority element. The majority element is the element that appears more than ⌊ n/2 ⌋ times. You may assume that the array is non-empty and the majority element always exist in the array. ...
活动作品【300题刷题挑战】leetcode力扣剑指 Offer 39. 数组中出现次数超过一半的数字 majorityElement 第二百四十九题 | 数学 30播放 ·1弹幕2021-08-11 23:27:01 主人,未安装Flash插件,暂时无法观看视频,您可以… 未经作者授权,禁止转载 力扣300题刷题挑战 第二百四十九题 数学 需要源码的请看: https://git...
229. Majority Element II Given an integer array of sizen, find all elements that appear more than⌊ n/3 ⌋times. Example 1: Input: nums = [3,2,3] Output: [3] Example 2: Input: nums = [1] Output: [1] Example 3: Input: nums = [1,2] ...
[LeetCode]Majority Element II Question Given an integer array of size n, find all elements that appear more than ⌊ n/3 ⌋ times. The algorithm should run in linear time and in O(1) space. 本题难度Medium。 投票法...
def majorityElement(self, nums): """ :type nums: List[int] :rtype: List[int] """ if not nums: return [] # 候选参数1,候选参数2,初始化可以为任意值,只要保证num1 != num2 即可 num1, num2 = 0, 1 count1, count2 = 0, 0 ...
在leetcode上验证过了.