System.out.println("majorityElement---输入:"+ Arrays.toString(arg) +" , 输出:"+ result +" , 用时:"+ ((end - start) /1000) +"微秒");int[] arg2 = {3,2,3,1,2,3,2,3};longstart2 = System.nanoTime();intresult2 = instance.majorityElement2(arg2);longend2 = System.nanoTime...
LeetCode 之 Majority Element 找出数组中出现次数大于n/2次的元素。 1.先排序,处于中间n/2处的元素必然是要求的元素,道理很简单,就算把其他元素全放在前半部分或者后半部分也都会占不满的,中间的永远是majority element; 2.暴力,把每个元素出现次数记录下来,一旦大于n/2,就结束。由于每次都要与之前遍历过的元素...
Given an array of size n, find the majority element. The majority element is the element that appearsmore than⌊ n/2 ⌋ times. You may assume that the array is non-empty and the majority element always exist in the array. 本题难度Easy。有3种算法分别是:哈希法、排序法...
leetcode 169 Majority Element 冰山查询 Given an array of size n, find the majority element. The majority element is the element that appears more than ⌊ n/2 ⌋ times. You may assume that the array is non-empty and the majority element always exist in the array. 思路: Find k differ...
Leetcode No.169 Majority Element(c++实现) 1. 题目 1.1 英文题目 Given an array nums of size n, return the majority element. The majority element is the element that appears more than ⌊n / 2⌋ times. You may assume that the majority element always exists in the array....
C++ 智能模式 1 2 3 4 5 6 class Solution { public: vector<int> majorityElement(vector<int>& nums) { } }; 已存储 行1,列 1 运行和提交代码需要登录 Case 1Case 2Case 3 nums = [3,2,3] 1 2 3 [3,2,3] [1] [1,2] Source ...
这道题出现在了王道的《2019数据结构考研复习指导》的18页,LeetCode中也有这道题。题目大意是:给定一个长度为n的数组,我们定义"主元素"为数组中出现次数超过⌊n/2⌋的元素。 Description Given an array of size n, find the majority element. The majority element is the element that appears more than...
https://leetcode.com/problems/majority-element-ii/ 求大多数的升级版,给定一个int数组,长度为n,找出长度超过n/3的所有int 题目要求只能用O(1)的存储空间,所以排除HashMap的方法目前只能摩尔投票法则 长度超过n/3的所有数字,最多存在两个 类比找n/2的方法,所以假设有两个int, ...
intmajorityElement(vector<int> &num) { intn = num.size(); sort(num.begin(),num.end()); returnnum[n/2]; } }; public class Solution { public int MajorityElement(int[] nums) { Array.Sort(nums); return nums[nums.Length/2]; ...
169. 多数元素 - 给定一个大小为 n 的数组 nums ,返回其中的多数元素。多数元素是指在数组中出现次数 大于 ⌊ n/2 ⌋ 的元素。 你可以假设数组是非空的,并且给定的数组总是存在多数元素。 示例 1: 输入:nums = [3,2,3] 输出:3 示例 2: 输入:nums = [2,