import pandas as pd class Solution(object): def longestCommonPrefix(self, strs): for i in strs: if len(i) > 200 or len(i) < 1: # 控制列表strs长度 return False if not i.islower(): # 限制strs每一个元素必须为小写 return False strs_dict = {} #为strs的每一个元素创建一个空字...
1、当strs为空,直接输出“” 2、当strs中含有“”,直接输出“” 3、strs[0]的最长长度由最短公共长度l决定(code line:15) 1classSolution:2#@return a string3deflongestCommonPrefix(self, strs):4ifstrs ==[]:5return""6foriinrange(1,len(strs)):7l1 =len(strs[0])8l2 =len(strs[i])...
class Solution: # @return a string def longestCommonPrefix(self, strs): if len( strs ) == 0: return '' if len( strs ) == 1: return strs[0] minstrslen = 9999 index = 0 for i in range( 0, len( strs ) ): if len( strs[i] ) < minstrslen: minstrslen = len( strs...
Runtime: 36 ms, faster than 34.95% of Python3 online submissions Memory Usage: 12.8 MB, less than 100.00% of Python3 online submissions classSolution:deflongestCommonPrefix(self,strs:List[str])->str:preStr=''ifnotlen(strs):# empty strsreturnpreStrforiinrange(len(strs[0])):firstLetter...
python # 方法一 时间O(mn),空间O(1) def longest_common_prefix(strs: [str]) -> str: """ 最长公共前缀 -> 纵向扫描 :param strs: [str] :return: str """ if not strs: return '' length, count = len(strs[0]), len(strs) ...
Leetcode: Longest Common Prefix 题目: Write a function to find the longest common prefix string amongst an array of strings. 即求给定的一组字符串的公共前缀。 思路分析: 一个一个寻找前缀,先比较第一个和第二个,找到公共前缀,然后公共前缀和第三个比较,寻找公共前缀,以此类推。
下面是一个简单的Python代码示例: ```python def longestCommonPrefix(strs): if not strs: return "" min_str = min(strs) max_str = max(strs) for i, char in enumerate(min_str): if char != max_str[i]: return min_str[:i] return min_str print(longestCommonPrefix(["flower", "...
classSolution{publicStringlongestCommonPrefix(String[]strs){if(strs==null||strs.length==0)return"";String prefix=strs[0];for(int i=1;i<strs.length;i++){while(strs[i].indexOf(prefix)!=0){prefix=prefix.substring(0,prefix.length()-1);if(prefix.isEmpty())return"";}}returnprefix;...
//Divide-and-Conquer Approach, python, 44ms class Solution { public: string longestCommonPrefix(vector<string>& strs) { if (strs.empty()) return ""; for (int pos = 0; pos < strs[0].length(); pos++) for (int i = 1; i < strs.size(); i++) ...
in strs: if len(elem)< lenth: lenth = len(elem) a = elem common_prefix = "" for i in range(lenth): #遍历每个字符串的前lenth位元素,判断是否每一位都与a相同 for s in strs: if s[i] != a[i]: return common_prefix common_prefix = common_prefix + a[i] return common_prefix ...