1、当strs为空,直接输出“” 2、当strs中含有“”,直接输出“” 3、strs[0]的最长长度由最短公共长度l决定(code line:15) 1classSolution:2#@return a string3deflongestCommonPrefix(self, strs):4ifstrs ==[]:5return""6foriinrange(1,len(strs)):7l1 =len(strs[0])8l2 =len(strs[i])...
Write a function to find the longest common prefix string amongst an array of strings. classSolution:#@return a string#最长公共前缀deflongestCommonPrefix(self, strs):ifstrsisNoneorstrs ==[]:return''result=''pre=Noneforcurinxrange(len(strs[0])):fornodeinstrs:iflen(node) <=cur:returnres...
Runtime: 36 ms, faster than 34.95% of Python3 online submissions Memory Usage: 12.8 MB, less than 100.00% of Python3 online submissions classSolution:deflongestCommonPrefix(self,strs:List[str])->str:preStr=''ifnotlen(strs):# empty strsreturnpreStrforiinrange(len(strs[0])):firstLetter...
prefix = lcp_handle(prefix, strs[i]) if not prefix: break return prefix if __name__ == "__main__": strs1 = ['flight', 'flies', 'fly'] print(longest_common_prefix(strs1)) # 此情况比较3*3=9 strs2 = ['skxxuard'] * 5 print(longest_common_prefix(strs2)) # 最坏情况,元...
费了不少劲写出代码后,发现leetcode上不能import package所以不能用 :< 题目: 编写一个函数来查找字符串数组中的最长公共前缀字符串。 如果没有公共前缀,则返回空字符串"" 示例1: 输入: strs = ["flower","flow","flight"] 输出: “fl” 示例2: 输入: strs = ["dog","racecar","car"] 输出:...
[Leetcode][python]Longest Common Prefix/最长公共前缀,题目大意寻找一组字符串的公共起始子串解题思路将每个字符串和第一个字符串对比,而且从第一个字母开始遍历,一旦出现某个字符串结束了,或者字母不同,则直接输出第一个字符串的前N个字母代码时间复杂度:O(n*k)k为
classSolution(object):deflongestCommonPrefix(self,strs):""":type strs:List[str]:rtype:str"""ifnot strs:return""foriinrange(len(strs[0])):forstringinstrs[1:]:# flow,flightifi>=len(string)or string[i]!=strs[0][i]:returnstrs[0][:i]returnstrs[0]...
LeetCode 14. Longest Common Prefix 给k个字符串,求出他们的最长公共前缀(LCP) 样例在 "ABCD" "ABEF" 和 "ACEF" 中, LC... 六尺帐篷阅读 2,380评论 0赞 5 leetCode 14 Longest Common Prefix https://leetcode.windliang.cc/ 第一时间发布 题目描述(简单难度) 解法一 垂直比... windliang阅读 187评...
public StringlongestCommonPrefix(String[]strs){if(strs==null||strs.length==0)return"";int minLen=Integer.MAX_VALUE;for(String str:strs)minLen=Math.min(minLen,str.length());int low=1;int high=minLen;while(low<=high){int middle=(low+high)/2;if(isCommonPrefix(strs,middle))low=middle...
You need to find the length of the longest common prefix between all pairs of integers(x, y)such thatxbelongs toarr1andybelongs toarr2. Return the length of the longest common prefix among all pairs. If no common prefix exists among them, return0. ...