return its level order traversal as: [ [3], [9,20], [15,7] ] 代码: /** * Definition for a binary tree node. * struct TreeNode { * int val; * TreeNode *left; * TreeNode *right; * TreeNode(int x) : val(x), left(NULL), right(NULL) {} * };*/classSolution {public: ...
Binary Tree Level Order Traversal(二叉树的层次遍历) HoneyMoose iSharkFly - 鲨鱼君 来自专栏 · Java 描述给出一棵二叉树,返回其节点值的层次遍历(逐层从左往右访问)样例给一棵二叉树 {3,9,20,#,#,15,7}:3 / \ 9 20 / \ 15 7返回他的分层遍历结果:[ [3], [9,20], [15,7] ]挑战挑战1...
* Definition for binary tree * struct TreeNode { * int val; * TreeNode *left; * TreeNode *right; * TreeNode(int x) : val(x), left(NULL), right(NULL) {} * };*/classSolution {private: vector<vector<int> >result;public:voidtraversal(TreeNode *root,intdepth) {if(root==NULL)ret...
* Definition for a binary tree node. * struct TreeNode { * int val; * TreeNode *left; * TreeNode *right; * TreeNode(int x) : val(x), left(NULL), right(NULL) {} * }; */ class Solution { public: vector<vector<int>> levelOrder(TreeNode* root) { vector<vector<int>>res; i...
return its bottom-up level order traversal as: [[15,7],[9,20],[3]] 1. 2. 3. 4. 5. 题目大意 按层序从下到上遍历一颗树。 解题思路 用一个队列即可实现。 参考代码 packageleetcodeimport("/halfrost/LeetCode-Go/structures")// TreeNode definetypeTreeNode=structures.TreeNode/** ...
add(c.val); if(c.left!=null) s2.push(c.left); if(c.right!=null) s2.push(c.right); } ans.add(tmp); tmp=new ArrayList<Integer>(); while(!s2.isEmpty()) { c=s2.pop(); tmp.add(c.val); if(c.right!=null)s1.push(c.right); if(c.left!=null)s1.push(c.left); } ...
Implementation of Data Structures in C stackqueuedata-structuresbinary-search-treedata-structruesbreadth-first-searchdepth-first-searchtree-traversalheapsort-algorithmdata-structures-algorithmssingly-linked-listdoubly-linked-listpriority-queuesqueue-algorithmdata-structures-and-algorithmslevel-order-traversaldynamic-...
return its bottom-up level order traversal as: [[15,7],[9,20],[3]] 二叉树的层次遍历,不过需要保持每一层的数据,可以通过vector配合队列实现,实现: classSolution{public:vector<vector<int>>levelOrderBottom(TreeNode*root){vector<vector<int>>vvi;if(root==NULL){returnvvi;}queue<TreeNode*>queue...
Binary Tree Zigzag Level Order Traversal.png 解題思路 : 主要是 BFS 用 queue 來實現 level order traversal 只是其中多加了一個 boolean 變數來決定是否要反向放入某一層的數值 我用 xor 來做 boolean 值的修改 另外 c++ 有內建的 reverse 函數 只要放入 vector 的 begin 跟 end 即可使用 ...
new_node->right = NULL; return new_node; } void tree::levelorder_traversal(node *root){ queue <node*> que; node *item; que.push(root); //insert the root at first while(!que.empty()){ item = que.front(); //get the element from the front end cout << item->value << " "...