* Definition for a binary tree node. * struct TreeNode { * int val; * TreeNode *left; * TreeNode *right; * TreeNode(int x) : val(x), left(NULL), right(NULL) {} * }; */classSolution{public: vector<vector<int>>levelOrder(TreeNode* root) { queue<TreeNode*>qt; TreeNode *pt...
TreeNode(intx) : val(x), left(NULL), right(NULL) {} };classSolution {public: list<vector<TreeNode>>levelNode; vector<vector<int>>allLevelval; vector<vector<int>> levelOrder(TreeNode *root) { vector<TreeNode>curVec; vector<int>curIntList;if(levelNode.empty() && root !=NULL){ cu...
Leetcode: Binary Tree Level Order Traversal II 题目: Given a binary tree, return thebottom-up level ordertraversal of its nodes' values. (ie, from left to right, level by level from leaf to root). For example: Given binary tree {3,9,20,#,#,15,7}, AI检测代码解...
Given a binary tree, return the zigzag level order traversal of its nodes’ values. (ie, from left to right, then right to left for the next level and alternate between). For example: Given binary tree [3,9,20,null,null,15,7], 3 / \ 9 20 / \ 15 7 return ...
Binary+Tree+Level+Order+Traversal">https://www.cwiki.us/display/ITCLASSIFICATION/Binary+Tree+Level+Order+Traversal</a>* <li>@see<a href=* "https://www.lintcode.com/problem/binary-tree-level-order-traversal">https://www.lintcode.com/problem/binary-tree-level-order-traversal</a>* </ul>...
这道题考的就是 BFS,我们可以通过 DFS 实现。只需要在递归过程中将当前 level 传入即可。 publicList<List<Integer>>levelOrder(TreeNoderoot){List<List<Integer>>ans=newArrayList<>();DFS(root,0,ans);returnans;}privatevoidDFS(TreeNoderoot,intlevel,List<List<Integer>>ans){if(root==null){return;}...
danieldotwav/Average-of-Levels-in-Binary-Tree Star3 Code Issues Pull requests A C++ program that efficiently calculates the average values of nodes at each level in a binary tree, employing a level-order traversal approach for accurate and fast computation. ...
这道题和LeetCode笔记:107. Binary Tree Level Order Traversal II是姊妹题,解题思路都是一样的,只是结果要求的顺序是反的,同样有两种方法,也就是经常说到的DFS深度优先遍历和BFS广度优先遍历。 BFS: 广度优先遍历就是一层层地攻略过去,把每一层的所有节点都记录下来再走向下一层。因为每层会有多个节点,不是简...
Binary Tree Level Order Traversal Given a binary tree, return the level order traversal of its nodes' values. (ie, from left to right, level by level). For example: Given binary tree [3,9,20,null,null,15,7], 3 / \ 9 20
这道题和Binary Tree Level Order Traversal很类似,都是层序遍历一棵树,只是这道题要求从最底层往最上层遍历。这道题我没有想到什么好的做法可以一次的自底向上进行层序遍历,能想到的就是进行Binary Tree Level Order Traversal中的遍历,然后对结果进行一次reverse。时间上和空间上仍是O(n)。代码如下: ...