Given a binary tree, return thelevel ordertraversal of its nodes' values. (ie, from left to right, level by level). For example: Given binary tree{3,9,20,#,#,15,7}, 3 / \ 9 20 / \ 15 7 return its level order traversal as: [ [3], [9,20], [15,7] ] ++++++++++++...
Given a binary tree, return thebottom-up level ordertraversal of its nodes' values. (ie, from left to right, level by level from leaf to root). For example: Given binary tree{3,9,20,#,#,15,7}, 3 / \ 9 20 / \ 15 7 return its bottom-up level order traversal as: [ [15,7...
Binary Tree Level Order Traversal(二叉树的层次遍历) HoneyMoose iSharkFly - 鲨鱼君 来自专栏 · Java 描述给出一棵二叉树,返回其节点值的层次遍历(逐层从左往右访问)样例给一棵二叉树 {3,9,20,#,#,15,7}:3 / \ 9 20 / \ 15 7返回他的分层遍历结果:[ [3], [9,20], [15,7] ]挑战挑战1...
offer(level); treeNode.offer(curNode.right); nodeLevel.offer(level); } } return ans; } 第二种方案 把102 题 的解释贴过来。 我们在 while 循环中加一个 for 循环,循环次数是循环前的队列中的元素个数即可,使得每次的 while 循环出队的元素都是同一层的元素。 for 循环结束也就意味着当前层结束了,...
AI检测代码解析 # Definition for a binary tree node. # class TreeNode: # def __init__(self, val=0, left=None, right=None): # self.val = val # self.left = left # self.right = right class Solution: def levelOrder(self, root: Optional[TreeNode]) -> List[List[int]]: ...
return its bottom-up level order traversal as: AI检测代码解析 [ [15,7], [9,20], [3] ] 1. 2. 3. 4. 5. 分析: 这道题目跟上道题目很相似 Leetcode: Binary Tree Level Order Traversal ,唯一不同的就是返回结果是从子叶节点到根节点,所以我们只需要将结果翻转下就好了!
queuecppbinary-treememory-managementtree-traversalcomputational-complexitylevel-order-traversalnode-averaging UpdatedJan 31, 2024 C++ Whether you're a coding novice or a seasoned pro, this repository has something invaluable to offer, ensuring growth in your problem-solving skills and coding prowess. ...
描述: Given a binary tree, return the level order traversal of its nodes' values. (ie, from left to right, level by level). For example:Given binary tree{3,9,20,#,#,15,7}, return its level order trav...
Binary Tree Level Order Traversal II是姊妹题,解题思路都是一样的,只是结果要求的顺序是反的,同样有两种方法,也就是经常说到的DFS深度优先遍历和BFS广度优先遍历。 BFS: 广度优先遍历就是一层层地攻略过去,把每一层的所有节点都记录下来再走向下一层。因为每层会有多个节点,不是简单的一个左节点一个右节点的...
insert_node(my_tree.root, 20); my_tree.root = my_tree.insert_node(my_tree.root, 15); my_tree.root = my_tree.insert_node(my_tree.root, 8); my_tree.root = my_tree.insert_node(my_tree.root, 23); cout << "Level-Order Traversal: "; my_tree.levelorder_traversal(my_tree.root...