代码语言:javascript 复制 classSolution:deftwoSum(self,nums,target):iflen(nums)<=1:returnFalse d=dict()foriinrange(len(nums)):ifnums[i]ind:return[d[nums[i]],i]else:d[target-nums[i]]=i 恩,最后找队友一起刷题。喜欢可以联系我
代码语言:javascript 复制 classSolution{public:vector<int>twoSum(vector<int>&nums,int target){vector<int>result;// 方法一:暴力搜索for(int i=0;i<nums.size();i++){for(int j=i+1;j<nums.size();j++){// 注意这里是从i+1开始,避免重复利用同一个元素if(target-nums[j]==nums[i]){result...
可以参考这个链接: 求和问题总结(leetcode 2Sum, 3Sum, 4Sum, K Sum),写的很清楚。 这里我只写了2Sum和3Sum的代码,注意要避免重复排序,同时避免重复数字的循环。 代码如下: import java.util.ArrayList; import java.util.Arrays; import java.util.List; public class Solution { //javascript:void(0) //K...
方法一:暴力枚举 classSolution{public:vector<int>twoSum(vector<int>& nums,inttarget){intn = nums.size();for(inti =0; i < n; ++i) {for(intj = i +1; j < n; ++j) {if(nums[i] + nums[j] == target) {return{i, j}; } } }return{}; } }; 方法二:哈希表 classSolution{pu...
The function twoSum should return indices of the two numbers such that they add up to the target, where index1 must be less than index2. Please note that your returned answers (both index1 and index2) are not zero-based. You may assume that each input would have exactly one solution....
/** * @作者:lao-la-rou-yue-jiao-yue-xiang * @链接:https://leetcode-cn.com/problems/two-sum/solution/xiao-bai-pythonji-chong-jie-fa-by-lao-la-rou-yue-j/ * @param {number[]} nums * @param {number} target * @return {number[]} */def twoSum(nums, target): lens = len(nums...
我用JS刷LeetCode | Day 1 | Two Sumwww.brandhuang.com/article/1583315258879 Question: Given an array of integers, returnindicesof the two numbers such that they add up to a specific target. You may assume that each input would haveexactlyone solution, and you may not use the same ele...
Runtime:104 ms, faster than 46.95% of JavaScript online submissions for Two Sum. Memory Usage:34.6 MB, less than 72.32% of JavaScript online submissions for Two Sum. 决定采用python方法做一遍,试一下有什么不同,代码如下: python 2: class Solution(object): ...
leetcode-445-两数相加II //与倒序不同,如果程序一开始没有reverse l1,不能直接返回l1,因为其依然指向原头结点,即现尾节点 class Solution { public: ListNode* reverseListNode(ListNode* head) { ListNode* pr...leetcode-2-两数相加· class Solution { public: ListNode* addTwoNumbers(ListNode* l1,...
提交记录 代码 测试用例 测试结果 测试结果 登录并分享题解 登录 1.2K 1.5M 1.4K 327 103.7K 103 432 12.4K 7 1 125 0 1 53 0 1 158 0 1 78 0 2 213 0 2 259 0 0 7K 0 0 5.3K 0 0 4.3K 0 0 3.1K 0 C++ 智能模式 1 2