循环遍历每个元素 xx 并查找是否有另一个值等于目标 xtarget−x。 classSolution:deftwoSum(self, nums, target):""" :type nums: List[int] :type target: int :rtype: List[int] """foriinrange(0,len(nums)):forjinrange(i+1,len(nums)):ifnums[i] + nums[j] == target:return[i,j] ...
This is the solution. 背诵:经典解法 class Solution: def twoSum(self, nums: List[int], target: int) -> List[int]: # 创建一个字典,用于记录每个元素最后出现的位置 num_dict = {num: idx for idx, num in enumerate(nums)} # 遍历列表nums中的每个数及其索引 for idx, num in enumerate(...
2、Python解法 我是这样写的 classSolution(object):deftwoSum(self,nums,target):""":type nums: List[int] :type target: int :rtype: List[int]"""foriinrange(0,len(nums)-1):forjinrange(i+1,len(nums)):ifnums[i]+nums[j]==target:returni,j nums=[2,7,11,15] target=9result=Soluti...
Runtime: 848 ms, faster than32.81%ofPython3online submissions forTwo Sum. 仍旧是连一半都没超过啊,娘匹西。 官方方法 Two-Pass Hash Table class Solution: def twoSum(self, nums: List[int], target: int) -> List[int]: hashTable = {} length = len(nums) for i in range(length): hashTabl...
node(intindex,intv):originalIndex(index),val(v){} }Node; boolcompare(constNode&a,constNode&b){ returna.val<b.val; } classSolution{ public: vector<int>twoSum(vector<int>&numbers,inttarget) { vector<int>result; intlength=numbers.size(); ...
class Solution: def twoSum(self, nums: List[int], target: int) -> List[int]: hashtable = dict() for i, num in enumerate(nums): if target - num in hashtable: return [hashtable[target - num], i] hashtable[nums[i]] = i ...
Python enumerate() 函数,用for来实现计数功能 enumerate()函数enumerate()函数用于将一个可遍历的数据对象(如列表、元组或字符串)组合为一个索引序列,同时列出数据和数据下标,一般用在 for 循环当中。enumerate(sequence, [start=0]) 举个例子: 例子来源 ...
Leetcode【1】twoSum(Python) 技术标签: leetcode python python leetcode 暴力法 class Solution(object): def twoSum(self,nums,target): """ :type nums: List[int] :type target: int :rtype: List[int] """ for i in range(len(nums)): for j in range(i+1,len(nums)): if nums[i]+...
【LeetCode】TwoSum 题目: Given an array of integers, return indices of the two numbers such that they add up to a specific target. You may assume that each input would have exactly one solution, and yo...leetcode - TwoSum 最简单的一道题开始刷题之旅。。。 Given an array of ...
The function twoSum should return indices of the two numbers such that they add up to the target, where index1 must be less than index2. Please note that your returned answers (both index1 and index2) are not zero-based. You may assume that each input would have exactly one solution....