5 这一步提供我的打败97%的人的代码实现代码：class Solution {public: vector<int> twoSum(vector<int>& nums, int target) { unordered_map<int,int > map; for(int i=0;i<nums.size();i++) { int val=nums[i]; auto iter=map.find(val); if (iter!=map.end()) ...
The problem "Two Sum" requires finding two numbers in aninteger arraysuch that their sum equals a specifiedtargetnumber. You need to returnthe indices ofthese two numbers, whereindices start from 0. The indices ofthe two numbers cannot be the same, and there isexactly one solutionfor each i...
1classSolution(object):2deftwoSum(self,nums,target):3"""4:type nums: List[int]5:type target: int6:rtype: List[int]7"""8n =len(nums)9result ={}10ifn <= 1:11returnFalse12else:13foriinrange(n):14ifnums[i]inresult:15returnresult[nums[i]],i16else:17result[target-nums[i]]=i...
} 发现对于leetcode而言貌似只能提交class Solution内部的部分。而compare函数放在Solution内部就会出错,放在Solution外面就正常。为什么??? 然后就通过重载圆括号写了函数对象,顺利通过。 1classSolution {//two sum O(nlogn)2public:3structNode{4intval;5intindex;6Node(intv,intidx) :val(v), index(idx){}7...
classSolution{public:vector<int>twoSum(vector<int>&nums,inttarget){unordered_map<int,int>num_map;for(inti=0;i<nums.size();i++){autoit=num_map.find(target-nums[i]);// 此处不需要去重判断,按照题目意思,数组中不存在重复数字// 因此在一次遍历的情况下,不会出现重复数字if(it!=num_map.end(...
Given an array nums of n integers and an integer target, are there elements a, b, c, and d in nums such that a + b + c + d = target? Find all unique quadruplets in the array which gives the sum of target. Note: The solution set must not contain duplicate quadruplets. Example...
class Solution: def twoSum(self, nums: List[int], target: int) -> List[int]: hashtable = dict() for i, num in enumerate(nums): if target - num in hashtable: return [hashtable[target - num], i] hashtable[nums[i]] = i ...
2. 两数相加 - 给你两个 非空 的链表,表示两个非负的整数。它们每位数字都是按照 逆序 的方式存储的,并且每个节点只能存储 一位 数字。 请你将两个数相加,并以相同形式返回一个表示和的链表。 你可以假设除了数字 0 之外,这两个数都不会以 0 开头。 示例 1: [ht
int*twoSum(int*nums,intnumsSize,inttarget,int*returnSize){inti,max,min;max=min=nums[0];for(i=0;i<numsSize;i++){if(nums[i]>max)max=nums[i];if(nums[i]<min)min=nums[i];}int*map=(int*)calloc((max-min+1),sizeof(int));int*result=(int*)malloc(2*sizeof(int));boolfound=fa...
classSolution{public:vector<int>twoSum(vector<int>&nums,int target){vector<int>result;// 方法一:暴力搜索for(int i=0;i<nums.size();i++){for(int j=i+1;j<nums.size();j++){// 注意这里是从i+1开始,避免重复利用同一个元素if(target-nums[j]==nums[i]){result.push_back(i);result....