The problem "Two Sum" requires finding two numbers in aninteger arraysuch that their sum equals a specifiedtargetnumber. You need to returnthe indices ofthese two numbers, whereindices start from 0. The indices ofthe two numbers cannot be the same, and there isexactly one solutionfor each i...
} 发现对于leetcode而言貌似只能提交class Solution内部的部分。而compare函数放在Solution内部就会出错,放在Solution外面就正常。为什么??? 然后就通过重载圆括号写了函数对象,顺利通过。 1classSolution {//two sum O(nlogn)2public:3structNode{4intval;5intindex;6Node(intv,intidx) :val(v), index(idx){}7...
5 这一步提供我的打败97%的人的代码实现代码：class Solution {public: vector<int> twoSum(vector<int>& nums, int target) { unordered_map<int,int > map; for(int i=0;i<nums.size();i++) { int val=nums[i]; auto iter=map.find(val); if (iter!=map.end()) ...
result[1] =jreturnresult[:]//返回结果} } }returnnil } 回到顶部 四、C代码 int* twoSum(int* nums,intnumsSize,inttarget) {int*a = (int*)malloc(2*sizeof(int));for(inti =0;i < numsSize;i++){for(intj = i +1;j < numsSize;j++){if(nums[j] == target -nums[i]){ a[0]...
classSolution{public:vector<int>twoSum(vector<int>&nums,inttarget){unordered_map<int,int>num_map;for(inti=0;i<nums.size();i++){autoit=num_map.find(target-nums[i]);// 此处不需要去重判断,按照题目意思,数组中不存在重复数字// 因此在一次遍历的情况下,不会出现重复数字if(it!=num_map.end(...
class Solution { public: vector<int> twoSum(vector<int>& nums, int target) { vector<int> vecResult; for( int i = 0; i < nums.size() - 1; ++i ) { for( int j = i + 1; j < nums.size(); ++j ) { if( nums[i] + nums[j] == target ) ...
class Solution: def twoSum(self, nums: List[int], target: int) -> List[int]: hashtable = dict() for i, num in enumerate(nums): if target - num in hashtable: return [hashtable[target - num], i] hashtable[nums[i]] = i ...
class Solution { public int[] twoSum(int[] nums, int target) { Map<Integer, Integer> map = new HashMap(); //存储到HashMap中 for (int i = 0; i < nums.length; i++){ map.put(nums[i], i); } //遍历数组 for (int i = 0; i < nums.length; i++) { ...
int*twoSum(int*nums,intnumsSize,inttarget,int*returnSize){int*result=(int*)malloc(2*sizeof(int));boolfound=false;for(inti=0;i<numsSize-1;i++){if(!found){for(intj=i+1;j<numsSize;j++){if(nums[i]+nums[j]==target){result[0]=i;result[1]=j;found=true;break;}}}if(found){...
class Solution { public ListNode addTwoNumbers(ListNode l1, ListNode l2) { ListNode head = null; ListNode tail = null; int ca = 0; while(l1!=null||l2!=null){ int i = l1==null?0:l1.val; int j = l2==null?0:l2.val; int sum = i + j + ca ; if(head == null){ head ...