public int[] twoSum(int[] numbers, int target) { int j = numbers.length-1; int[] output = new int[2]; if(numbers[0] >= 0) while(numbers[j] > target && j >= 0) --j; //System.out.println("j="+j); for(; j >= 0; j--){ int diff = target - numbers[j]; int r...
玩转力扣之LeetCode 1 - 两数之和【轻松刷LeetCode】LeetCode 1. 两数之和 英文题目: 2 sum (Two sum) 难度: 简单 给定一个整数数组 nums 和一个整数目标值 target,请你在该数组中找出 和为目标值 target 的那 两…
1classSolution {2public:3vector<int> twoSum(vector<int> &numbers,inttarget) {45vector<int>result;6map<int,int>hashMap;78for(inti =0; i < numbers.size(); i++) {910if(!hashMap.count(numbers[i]))11hashMap.insert(pair<int,int>(numbers[i], i));//<value, key>1213if(hashMap.co...
Given an array of integers that is already sorted in ascending order, find two numbers such that they add up to a specific target number. The function twoSum should return indices of the two numbers such that they add up to the target, where index1 must be less than index2. Note: Your...
1. Two Sum (2 sum) 提交网址: https://leetcode.com/problems/two-sum/ Total Accepted: 216928 Total Submissions:953417 Difficulty:Easy ACrate: 22.8% Given an array of integers, return indices of the two numbers such that they add up to a specific target. You may assume that each input ...
2 问题的示例：给定nums = [2,7,11,15]， target = 9，因为nums[0] + nums[1] = 2 + 7 = 9，返回[0,1]。3 输入与输出：vector<int> twoSum(vector<int>& nums, int target){}完成这个成员函数解决问题。4 思路：这个可以使用哈希表一次搞定这个问题。当我们扫描整个数组，检查当前元素的补码是否...
解释: 2 与 7 之和等于目标数 9 。因此 index1 = 1, index2 = 2 。 解法一: 暴力求解法 对于初学者来说,没有接触过双指针相关的问题,依然是首先会想到暴力求解的方法 classSolution{publicint[]twoSum(int[]numbers,inttarget){for(inti=0;i<numbers.length;i++){for(intj=i+1;j<numbers.length;...
Given an array of integers, find two numbers such that they add up to a specific target number. The function twoSum should return indices of the two numbers suchthat they add up to the target, where index1 must be less than index2.Please note that your returned answers (both index1 and...
[-1, -1, 2] ] 这个问题很经典,对于3Sum,先确定一个数字,然后这个问题就退化成了2Sum的问题。针对2Sum,先对数组排序,然后使用双指针匹配可行解就可以解决,虽然可以考虑使用HashMap加速搜索,但是对于本题使用HashMap的与否的时间复杂度都一样,都是O(nlog(n))。可以参考这个链接: 求和问题总结(leetcode 2Sum...
输入:nums = [2,7,11,15], target = 9 输出:[0,1] 解释:因为nums[0] + nums[1] == 9 ,返回 [0, 1] 。 示例2: 输入:nums = [3,2,4], target = 6 输出:[1,2] 示例3: 输入:nums = [3,3], target = 6 输出:[0,1] 提示: 2 <= nums.length <= 104 -109 <= nums[...