玩转力扣之LeetCode 1 - 两数之和【轻松刷LeetCode】LeetCode 1. 两数之和 英文题目: 2 sum (Two sum) 难度: 简单 给定一个整数数组 nums 和一个整数目标值 target,请你在该数组中找出 和为目标值 target 的那 两…
publicint[]twoSum(int[]nums,inttarget){inti=0;intj=nums.length-1;while(i<j){intsum=nums[i]+nums[j];if(sum<target){i++;}elseif(sum>target){j--;}else{returnnewint[]{i,j};}}returnnewint[]{-1,-1};} 代码的逻辑很简单,就轻轻巧巧地使用了两个指针,一个只向左移动,一个只向右移...
Output: [1,2] Explanation: The sum of 2 and 7 is 9. Therefore index1 = 1, index2 = 2. 方法一: int* twoSum(int* numbers,intnumbersSize,inttarget,int*returnSize) {*returnSize =2;int*Array =NULL;for(inti =1; i < numbersSize; i++) {for(intj =0; j < i; j++) {if(number...
Given an array of integers that is already sorted in ascending order, find two numbers such that they add up to a specific target number. The function twoSum should return indices of the two numbers such that they add up to the target, where index1 must be less than index2. Note: Your...
def twoSum(self, nums: List[int], target: int) -> List[int]:hashtable = dict()for i, num in enumerate(nums):if target - num in hashtable:return [hashtable[target - num], i]hashtable[nums[i]] = i return []官方给出的答案里，有些函数和语句可能不太了解，这里我说明一下 ● dic...
3 输入与输出：vector<int> twoSum(vector<int>& nums, int target){}完成这个成员函数解决问题。4 思路：这个可以使用哈希表一次搞定这个问题。当我们扫描整个数组，检查当前元素的补码是否已经存在于表中。如果存在，我们已经找到解决方案并立即返回。如果不存在就向表中插入该元素。5 这一步提供我的打败97%的人...
如果sum>target,则指针right向左边较小的数移动一位, 直到sum=target,获得题目所需要的解, 注意需要使用Map记录原来的数字对应的索引位置, 这里要求数组里面的整数不能重复。 这个算法的时间复杂度是O(n)。 publicint[]twoSumV2(int[]nums,inttarget){int[]results=newint[2];//记录原来的数对应的索引位置Map...
//K sum 可以递归去做 /* * 2Sum问题的求解:排序外加双指针来实现 * */ public List<List<Integer>> twoSum(int[] nums,int target) { List<List<Integer>> twoResList=new ArrayList<>(); Arrays.sort(nums); int i=0,j=nums.length-1; ...
two-sum public class TwoSum { public static void main(String[] args) { int[] nums = { 1, 3, 4, 5, 6 }; int[] result = twoSum(nums, 10); System.out.println("result[0]:" + result[0] + ", result[1]=" + result[1]); result = twoSum2(nums, 10); System.out.println...
Given an array of integers, find two numbers such that they add up to a specific target number. The function twoSum should return indices of the two numbers suchthat they add up to the target, where index1 must be less than index2.Please note that your returned answers (both index1 and...