Explanation:"i" and "love"are the two most frequent words. Note that"i" comes before "love"due to a lower alphabetical order. Example2: Input: ["the", "day", "is", "sunny", "the", "the", "the", "sunny", "is", "is"], k = 4Output: ["the", "is", "sunny", "day"]...
Can you solve this real interview question? Top K Frequent Words - Given an array of strings words and an integer k, return the k most frequent strings. Return the answer sorted by the frequency from highest to lowest. Sort the words with the same frequ
leetcode 692. Top K Frequent Words Given a non-empty list of words, return the k most frequent elements.Your answer should be sorted by frequency from highest to lowest. If two words have the same frequency, then the word with the lower alphabetical order comes first....
都是先用一个HashMap统计频率,然后再创建一个PriorityQueue对String进行排序,最后输出前k个String。我之前写的是lambda表达式,这次则采用了匿名类写法。https://blog.csdn.net/qq_31361913/article/details/10645538...LeetCode 692. Top K Frequent Words 题目: Given a non-empty list of words, return the k...
347. Top K Frequent ElementsMedium Topics Companies Given an integer array nums and an integer k, return the k most frequent elements. You may return the answer in any order. Example 1: Input: nums = [1,1,1,2,2,3], k = 2 Output: [1,2] Example 2: Input: nums = [1], k ...
LeetCode笔记:347. Top K Frequent Elements 问题: Given a non-empty array of integers, return the k most frequent elements. For example, Given [1,1,1,2,2,3] and k = 2, return [1,2]. Note: You may assume k is always valid, 1 ≤ k ≤ number of ......
[leetcode] 347. Top K Frequent Elements Description Given a non-empty array of integers, return the k most frequent elements. Example 1: Input: AI检测代码解析 nums = [1,1,1,2,2,3], k = 2 1. Output: AI检测代码解析 [1,2]
https://leetcode.com/problems/top-k-frequent-elements/ Given a non-empty array of integers, return the k most frequent elements. For example, Given [1,1,1,2,2,3] and k = 2, return [1,2]. Note: You may assume k is always valid, 1 ≤ k ≤ number of unique elements. ...
vector<string> topKFrequent(vector<string>& words,intk) { vector<string>res(k); unordered_map<string,int>freq; auto cmp= [](pair<string,int>& a, pair<string,int>&b) {returna.second > b.second || (a.second == b.second && a.first <b.first); ...
Explanation: "the", "is", "sunny" and "day" are the four most frequent words, 经典办法是使用哈希与数组原生的sort方法,sort里面先比较频率,然后再用字符串的localeCompare比较字符。 var topKFrequent = function(words, k) { var hash = {}; for (var i = 0; i < words.length; i++) { ...