Search in a Sorted Infinite Array (medium) Minimum Difference Element (medium) Bitonic Array Maximum (easy) 12. Pattern: Top ‘K’ Elements,前K个系列 任何让我们求解最大/最小/最频繁的K个元素的题,都遵循这种模式。 用来记录这种前K类型的最佳数据结构就是堆了(译者注:在Java中,改了个名,叫优先队...
Leetcode: Sort Transformed Array Given a sorted array of integers nums and integer values a, b and c. Apply a function of the form f(x) = ax2 + bx +c to each element x in the array. The returned array must be in sorted order. Expected time complexity: O(n) Example: nums= [-...
[LeetCode-88]-Merge Sorted Array(有序数组合并) 0. 题目相关 【题目解读】 给定两个有序数组,对数组进行合并操作。要求合并后的数组依旧有序。 【原题描述】原题链接 Given two sorted integer arrays nums1 and nums2, merge nums2 into nums1 as one sorted array. Note: The number of elements initi...
animation if no swaps occurred # Main execution part if __name__ == "__main__": # Define the unsorted array unsorted_arr = [74, 55, 35, 79, 57, 71, 81, 5, 82, 1] # Perform bubble sort and get the sorted array with step count sorted_arr, steps = bubble_sort(unsorted_arr...
leetcode:Merge Sorted Array (合并排好序的数组) Question:Given two sorted integer arrays A and B, merge B into A as one sorted array. Note: You may assume that A has enough space (size that is greater or equal tom+n) to hold additional elements from B. The number of elements ...
For k = 2, you should return: 2->1->4->3->5 For k = 3, you should return: 3->2->1->4->5 【解答】引入一个伪节点作为头,可以免去对 head 的特殊处理。基本思路是:一个快指针,一个慢指针,平时慢指针不动,快指针往前跑,在二者间距达到 k 时,令 start=slow.next,end=fas...
vector<int> nums; for (auto l : lists) //把所有链表的值都放入nums 统一排序再转换成链表; { while (l != NULL) { nums.push_back(l->val); l = l->next; } } sort(nums.begin(), nums.end()); if(nums.size()==0) return head; ...
LeetCode 88. Merge Sorted Array LeetCode 278. First Bad Version LeetCode 98. Validate Binary Search Tree LeetCode 173. Binary Search Tree Iterator LeetCode 238. Product of Array Except Self LeetCode 56. Merge Intervals LeetCode 75. Sort Colors ...
nums.sort_unstable(); ifletOk(_)=nums.binary_search(&target){ returntrue; } returnfalse; } } 注意:要使用排序的时候请注意,rust提供了sort和sort_unstable两个函数,第一个是稳定排序,第二个是不稳定排序,就是值相同的元素在稳定排序之后的相对位置不会改变,但是在不稳定排序之后就是完全不确定的相对位...
class Solution { public: int threeSumClosest(vector<int>& nums, int target) { sort(nums.begin(), nums.end()); int res = nums[0] + nums[1] + nums[2]; for(int i = 0; i < nums.size() - 2; i++){ int j = i + 1, k = nums.size() - 1; while(j < k){ int num...