Two pointers i and j are initialized to 0, pointing to the current elements of the left and right arrays, respectively. Comparison and Merging: The method iterates through both arrays, comparing the current elements of the left and right arrays. The smaller element is added to the sorted_arr...
classSolution {publicString largestNumber(int[] nums) {//解法一String[] str=newString[nums.length];for(inti=0;i<nums.length;i++){ str[i]=String.valueOf(nums[i]); } Arrays.sort(str,(o1,o2)->(o2+o1).compareTo(o1+o2)); StringBuilder sb=newStringBuilder();for(String s:str){ sb...
【Leetcode179】最大数(Arrays.sort自定义比较器) 一、题目 二、思路 可以先将数组元素逐个转为字符串后,直接通过java中的a.compareTo(b)方法进行比较,它会从头到尾根据ASCII码比较字符的大小; 在Array.sort()中如果使用自定义比较器Comparator,这里我们并不...
Arrays.sort(nums); 正常答案 class Solution { public void swap(int[] nums, int i, int j) { int t = nums[i]; nums[i] = nums[j]; nums[j] = t; } public void sortColors(int[] nums) { int r = 0, b = nums.length - 1, i = 0; while(i <= b) { if(nums[i] == ...
LeetCode--350. Intersection of Two Arrays II(两个数组的交集)Python 题目: 给定两个数组,返回这两个数组的交集。 解题思路: 使用哈希表用来存储第一个数组中的内容。再遍历第二个数组,看该数组的数字是否在哈希表中,在则将该数字加入输出的列表中。 代码(Python):......
题目地址:https://leetcode.com/problems/sort-an-array/ 题目描述 Given an array of integers nums, sort the array in ascending order. Example 1: Input: [5,2,3,1]Output: [1,2,3,5] Example 2: Input: [5,1,1,2,0,0]Output: [0,0,1,1,2,5] ...
leetcode 75 | 颜色分类(一次遍历排序) 编程算法 给定一个包含红色、白色和蓝色,一共 n 个元素的数组,原地对它们进行排序,使得相同颜色的元素相邻,并按照红色、白色、蓝色顺序排列。 ACM算法日常 2019/03/01 9840 75. 分类颜色 arrayssort排序原理 给定一个包含红色、白色和蓝色,一共 n 个元素的数组,原地对它...
classSolution{publicStringlargestNumber(int[]nums){intn=nums.length;StringnumsToWord[]=newString[n];for(inti=0;i<n;i++){numsToWord[i]=String.valueOf(nums[i]);}Arrays.sort(numsToWord,(a,b)->{return(b+a).compareTo(a+b);});//如果排序后的第一个元素是0,那后面的元素肯定小于或等...
922. Sort Array By Parity II # 题目 # Given an array A of non-negative integers, half of the integers in A are odd, and half of the integers are even. Sort the array so that whenever A[i] is odd, i is odd; and whenever A[i] is even, i is even. You may
var findMedianSortedArrays = function(nums1, nums2) { let num = nums1.concat(nums2); num = num.sort((a, b) => a - b); let mid = Math.floor(num.length / 2); if (num.length % 2 === 0) { return (num[mid-1] + num[mid])/2 ...