class Solution: def merge_sort(self, nums): # If the array length is less than or equal to 1, return the array (base case for recursion) if len(nums) <= 1: return nums # Find the middle point mid = len(nums) // 2 # Recursively sort the left half left_half = self.merge_sort...
Leetcode 912. Sort an Array题意: 就是给一个数组 然后排序 参考: 花花酱 LeetCode 912. Sort an Array 解法一:快速排序 时间复杂度: O(nlogn) ~ O(n^2) 空间复杂度:O(logn) ~ O(n) class Solution { public:…
classSolution{public:vector<int>sortArray(vector<int>& nums){mergeSort(nums,0, (int)nums.size() -1);returnnums; }voidmergeSort(vector<int>& nums,intstart,intend){if(start >= end)return;intmid = (start + end) /2;mergeSort(nums, start, mid);mergeSort(nums, mid +1, end);merge(...
classSolution{public:vector<int>sortArray(vector<int>& nums){returnmergeSort(nums,0, nums.size()); }// sort nums[start, end)vector<int>mergeSort(vector<int>& nums,intstart,intend){if(start +1== end)returnvector<int>(1, nums[start]);intL = end - start; vector<int> A =mergeSort...
Can you solve this real interview question? Sort an Array - Given an array of integers nums, sort the array in ascending order and return it. You must solve the problem without using any built-in functions in O(nlog(n)) time complexity and with the smal
leetcode 912 排序数组 sort-an-array【ct】,思路:快速排序soeasy一次通过啦
util.Arrays; public class Solution { // 选择排序:每一轮选择最小元素交换到未排定部分的开头 public int[] sortArray(int[] nums) { int len = nums.length; // 循环不变量:[0, i) 有序,且该区间里所有元素就是最终排定的样子 for (int i = 0; i < len - 1; i++) { // 选择区间 [...
题目:Given an array S of n integers, are there elements a, b, c in S such that a + b + c = 0? Find all unique triplets in the array which gives the sum of zero. Note: The solution set must not contain duplicate triplets. For example, given array S = [-1, 0, 1, 2, -...
classSolution:defsingleNumber(self,nums:List[int])->int:nums.sort()returnlist(set(nums[::2])^set(nums[1::2])) 思路三:位运算 异或的特点是相同为0不同为1,因此第一轮对所有元素进行异或操作,得到两个不同元素的异或结果(mark=a^b)。通过计算mark&(-mark)保留mark中从右起第一个1,其余位置变...
leetcode 912: sort-an-array leetcode 8: string-to-integer-atoi leetcode 56: merge-intervals - 先把数组按照起始下标排序,然后遍历,如果new end小于end,说明有重叠,那么就取start的最小值,end的最大值 leetcode 500:keyboard-row 返回字母在同一行的字符串 ...