class Solution: def merge_sort(self, nums): # If the array length is less than or equal to 1, return the array (base case for recursion) if len(nums) <= 1: return nums # Find the middle point mid = len(nums) // 2 # Recursively sort the left half left_half = self.merge_sort...
Leetcode 912. Sort an Array题意: 就是给一个数组 然后排序 参考: 花花酱 LeetCode 912. Sort an Array 解法一:快速排序 时间复杂度: O(nlogn) ~ O(n^2) 空间复杂度:O(logn) ~ O(n) class Solution { public:…
classSolution{public:vector<int>sortArray(vector<int>& nums){mergeSort(nums,0, (int)nums.size() -1);returnnums; }voidmergeSort(vector<int>& nums,intstart,intend){if(start >= end)return;intmid = (start + end) /2;mergeSort(nums, start, mid);mergeSort(nums, mid +1, end);merge(...
classSolution{public:vector<int>sortArray(vector<int>& nums){returnmergeSort(nums,0, nums.size()); }// sort nums[start, end)vector<int>mergeSort(vector<int>& nums,intstart,intend){if(start +1== end)returnvector<int>(1, nums[start]);intL = end - start; vector<int> A =mergeSort...
Can you solve this real interview question? Sort an Array - Given an array of integers nums, sort the array in ascending order and return it. You must solve the problem without using any built-in functions in O(nlog(n)) time complexity and with the smal
leetcode 912 排序数组 sort-an-array【ct】,思路:快速排序soeasy一次通过啦
{i:number;p:number;h:number;d:string;}letrobots:robot[]=[];//从左至右(排序后的下标)遍历机器人并判断当前机器人的方向positions.forEach((v,i)=>robots.push({i:i,p:v,h:healths[i],d:directions[i]}));robots.sort((a,b)=>a.p-b.p);for(leti=0;i<robots.length;){/**比较与栈...
题目:Suppose an array sorted in ascending order is rotated at some pivot unknown to you beforehand.(i.e., 0 1 2 4 5 6 7 might become 4 5 6 7 0 1 2).You are given a target value to search. If found in the array return its index, otherwise return -1.You may assume no dupli...
Can you solve this real interview question? Sort Array by Increasing Frequency - Given an array of integers nums, sort the array in increasing order based on the frequency of the values. If multiple values have the same frequency, sort them in decreasing
leetcode 912: sort-an-array leetcode 8: string-to-integer-atoi leetcode 56: merge-intervals - 先把数组按照起始下标排序,然后遍历,如果new end小于end,说明有重叠,那么就取start的最小值,end的最大值 leetcode 500:keyboard-row 返回字母在同一行的字符串 ...