参考: 花花酱 LeetCode 912. Sort an Array解法一:快速排序 时间复杂度: O(nlogn) ~ O(n^2) 空间复杂度:O(logn) ~ O(n) class Solution { public: vector<int> sortArray(vector<int>& nums) { sort(nums , 0 , nums.size() - 1); return nums; } //快速排序 //左闭右闭 void sort...
class Solution: def merge_sort(self, nums): # If the array length is less than or equal to 1, return the array (base case for recursion) if len(nums) <= 1: return nums # Find the middle point mid = len(nums) // 2 # Recursively sort the left half left_half = self.merge_sort...
classSolution{public:vector<int>sortArray(vector<int>& nums){returnmergeSort(nums,0, nums.size()); }// sort nums[start, end)vector<int>mergeSort(vector<int>& nums,intstart,intend){if(start +1== end)returnvector<int>(1, nums[start]);intL = end - start; vector<int> A =mergeSort...
vector<int> sortArray(vector<int>& nums) { quickSort(nums, 0, nums.size()); return nums; } // sort nums[start, end) void quickSort(vector<int>& nums, int start, int end) { if (end - start <= 1) return; // nums[j] in right position int j = partition(nums, start, end)...
【leetcode】912. Sort an Array 题目如下: Given an array of integersnums, sort the array in ascending order. Example 1: Input: [5,2,3,1] Output: [1,2,3,5] Example 2: Input: [5,1,1,2,0,0] Output: [0,0,1,1,2,5]
这里的排序是通过sort进行排序的哈~~~ 2.3.2第二种代码 如下所示: 代码语言:javascript 代码运行次数:0 运行 AI代码解释 classMedianFinder{//创建一个大根堆,小根堆PriorityQueue<Integer>maxHeap;PriorityQueue<Integer>minHeap;publicMedianFinder(){maxHeap=newPriorityQueue<>((a,b)->b-a);minHeap=newPriority...
题目:Given an array S of n integers, find three integers in S such that the sum is closest to a given number, target. Return the sum of the three integers. You may assume that each input would have exactly one solution. For example, given array S = {-1 2 1 -4}, and target =...
Given an array nums, write a function to move all 0’s to the end of it while maintaining the relative order of the non-zero elements. Example: Input: [0,1,0,3,12] Output: [1,3,12,0,0] Note: You must do this in-place without making a copy of the array. Minimize the total...
Remove Duplicates from Sorted Array // 时间复杂度O(n)，空间复杂度O(1) class Solution { public...
915 Partition Array into Disjoint Intervals 43.90% Medium 914 X of a Kind in a Deck of Cards 34.00% Easy 913 Cat and Mouse 29.90% Hard 912 Sort an Array 62.90% Medium 911 Online Election 48.30% Medium 910 Smallest Range II 24.90% Medium 909 Snakes and Ladders 36.10% Easy 908 Smallest ...