一、题目大意 https://leetcode.cn/problems/sort-characters-by-frequency 给定一个字符串 s ,根据字符出现的 频率 对其进行 降序排序 。一个字符出现的 频率 是它出现在字符串中的次数。 返回 已排序的字符串 。如果有多个答案,返回其中任何一个。 示例1: 输入: s = "tree" 输出: "eert" 解释: 'e'出...
func frequencySort(s string) string { // chToCnt[ch] 表示 s 中 ch 的出现次数 chToCnt := make(map[rune]int) for _, ch := range s { chToCnt[ch] += 1 } // 对 s 中的字符按照出现次数降序排序, // 出现次数相同时,按字符升序排序(以保证相同字符在一起) chs := ([]rune)(s)...
Given a strings, sort it indecreasing orderbased on thefrequencyof the characters. Thefrequencyof a character is the number of times it appears in the string. Returnthe sorted string. If there are multiple answers, returnany of them.
所以在这种情况下,把数组换成Map / Tree Map是比较好的做法,可以有效避免空间浪费,且具有排序的功能(C++std::map内部是一颗红黑树),最后构造结果的时候从map的最大key开始遍历就可以了: stringfrequencySort(string s){if(s.empty())return""; unordered_map<char,int> cnt;for(autoc : s) { cnt[c]++;...
【Leetcode】451. Sort Characters By Frequency https://leetcode.com/problems/sort-characters-by-frequency/#/description 特殊的排序,对频率排序。 1.常规思路,先遍历一遍,把频数存入map,再把map的entry存入priorityqueue,最后逐一出队即可。代码:...
451_(根据字符出现频率排序)Sort Characters by Frequency 1 问题描述、输入输出与样例 1.1 问题描述 给定一个字符串,请将字符串里的字符按照出现的频率降序排列。 1.2 输入与输出 输入: string s:给定的字符串s 输出: string:字符串里的字符按照出现的频率降序排列后的字符串 ...
https://leetcode-cn.com/problems/sort-characters-by-frequency/ Given a string s, sort it in decreasing order based on the frequency of the characters. The frequency of a character is the number of times it appears in the string.
Leetcode: Sort Characters By Frequency Given a string, sort it in decreasing order based on the frequency of characters. Example1: Input:"tree"Output:"eert"Explanation:'e' appears twicewhile'r' and 't'both appear once. So'e' must appear before both 'r' and 't'. Therefore "eetr"is ...
0451-Sort-Characters-By-Frequency/cpp-0451 CMakeLists.txt main.cpp 0454-4Sum-II 0455-Assign-Cookies 0470-Implement-Rand10-Using-Rand7 0473-Matchsticks-to-Square 0474-Ones-and-Zeroes 0478-Generate-Random-Point-in-a-Circle 0485-Max-Consecutive-Ones 0490-The-Maze 0494-Target-Sum 0497-Random-Poin...
1. Description Sort Characters By Frequency 2. Solution boolcompare(pair<char,int>&a,pair<char,int>&b){returna.second>b.second;}class Solution{public:stringfrequencySort(string s){map<char,int>stat;for(inti=0;i<s.length();i++){stat[s[i]]++;}vector<pair<char,int>>values;for(auto...