【leetcode】1636. Sort Array by Increasing Frequency 题目如下: Given an array of integersnums, sort the array in increasing order based on the frequency of the values. If multiple values have the same frequency, sort them in decreasing order. Return thesorted array. Example 1: Input: nums =...
Counter(nums) temp = sorted(dic.items(), key=lambda d:(d[1],-d[0])) nums = [] for i in range(len(temp)): times = temp[i][1] while times: nums.append(temp[i][0]) times -= 1 return nums 分类: LeetCode 标签: Array 好文要顶 关注我 收藏该文 微信分享 老鼠司令 粉丝...
leetcode 1636. Sort Array by Increasing Frequency (python) 描述 Given an array of integers nums, sort the array in increasing order based on the frequency of the values. If multiple values have the same frequency, sort them in decreasing order. Return the sorted array. Example 1: Input: ...
2. Your script should output the following, sorted by descending frequency: the 4 is 3 sunny 2 day 1 1. 2. 3. 4. Note: Don't worry about handling ties, it is guaranteed that each word's frequency count is unique. Could you write it in one-line using Unix pipes? 1. 2. 解题思...
1classSolution {2func numSmallerByFrequency(_ queries: [String], _ words: [String]) ->[Int] {3varres =[Int]()45let f = { (s: String) -> Intin6vara = [Int](repeating:0, count:26)7let chars = s.map{ $0}8forcinchars {9a[Int(c.asciiValue! - Character("a").asciiValue!
Given an array of integersnums, sort the array in increasing order based on the frequency of the values. If multiple values have the same frequency, sort them in decreasing order. Return thesorted array. Example 1: Input: nums = [1,1,2,2,2,3] ...