1: intsingleNumber(int A[], int n) { 2: int left = A[0]; 3:for(int i =1;i< n;i++) 4: { 5: left = left ^ A[i]; 6: } 7: return left; 8: }
于是利用交换律可以将数组假想成相同元素全部相邻,于是将所有元素依次做异或操作,相同元素异或为0,最终剩下的元素就为Single Number。时间复杂度O(n),空间复杂度O(1) 1classSolution {2public:3intsingleNumber(intA[],intn) {45//异或6intelem =0;7for(inti =0; i < n ; i++) {8elem = elem ^A[...
[1].https://github.com/chefyuan/algorithm-base [2].https://leetcode-cn.com/problems/single-number-ii/solution/ti-yi-lei-jie-wei-yun-suan-yi-wen-dai-ni-50dc/ [3].https://blog.csdn.net/White_Idiot/article/details/70178127 [4].https://blog.csdn.net/qq_30374549/article/details/89520...
class Solution { public int singleNumber(int[] nums) { int x = 0; for (int num : nums) // 1. 遍历 nums 执行异或运算 x ^= num; return x; // 2. 返回出现一次的数字 x } } 说明: 通过遍历数组中的每个数字,并使用异或运算将结果保存在result变量中,最终返回result即可。 C语言版本 #in...
For the purpose of this problem, we define empty string as valid palindrome. 【解答】注意大小写,注意数字和字母都要算有效字符。 代码语言:javascript 代码运行次数:0 运行 AI代码解释 public class Solution { public boolean isPalindrome(String s) { int left = 0; int right = s.length()-1; whil...
133 Clone Graph Medium Solution.java 136 Single Number Easy Solution.java 139 Word Break Medium Solution.java 146 LRU Cache Medium Solution.java 151 Reverse Words in a String Medium Solution.java 162 Find Peak Element Medium Solution.java 167 Two Sum II - Input Array Is Sorted Medium Solution...
挣扎了一段时间,就去讨论区看解答(https://leetcode.com/problems/strong-password-checker/discuss/91003/O(n%29-java-solution-by-analyzing-changes-allowed-to-fix-each-problem)去了: 代码语言:javascript 代码运行次数:0 运行 复制 class Solution { public int strongPasswordChecker(String s) { int res...
README.md single number ii Oct 21, 2015 solution.h the skyline problem Sep 8, 2015 Repository files navigation README Binary Tree Postorder Traversal (145) 要求不用递归实现后序遍历 后序是left-right-root,那么首先用修正的前序root-right-left,然后reverse一下,变成left-right-root就行了,代码如下...
(,, ): HDU 1542 Atlantis update: query: HDU 1828 Picture update: query: Title Solution Difficulty Time Space O(n log 218. The Skyline Problem Go Hard O(n) n) 307. Range Sum Query - Go Hard O(1) O(n) Mutable 315. Count of Smaller O(n log Go Hard O(n) Numbers After Self ...
LeetCode 刷题随手记 - 第一部分 前 256 题(非会员),仅算法题,的吐槽 https://leetcode.com/problemset/algorithms/...