1: intsingleNumber(int A[], int n) { 2: int left = A[0]; 3:for(int i =1;i< n;i++) 4: { 5: left = left ^ A[i]; 6: } 7: return left; 8: }
于是利用交换律可以将数组假想成相同元素全部相邻,于是将所有元素依次做异或操作,相同元素异或为0,最终剩下的元素就为Single Number。时间复杂度O(n),空间复杂度O(1) 1classSolution {2public:3intsingleNumber(intA[],intn) {45//异或6intelem =0;7for(inti =0; i < n ; i++) {8elem = elem ^A[...
class Solution { public int singleNumber(int[] nums) { int x = 0; for (int num : nums) // 1. 遍历 nums 执行异或运算 x ^= num; return x; // 2. 返回出现一次的数字 x } } 说明: 通过遍历数组中的每个数字,并使用异或运算将结果保存在result变量中,最终返回result即可。 C语言版本 #in...
public int singleNumber(int[] nums) { int ans = 0; for (int i = 0; i < nums.length; i++) { //异或运算 ans ^= nums[i]; } return ans; } ⏰ 时间复杂度:O(n) 空间复杂度:O(1) LeetCode137. 只出现一次的数字 II ☕ 题目:137. 只出现一次的数字 II (leetcode-cn.com/pr...
挣扎了一段时间,就去讨论区看解答(https://leetcode.com/problems/strong-password-checker/discuss/91003/O(n%29-java-solution-by-analyzing-changes-allowed-to-fix-each-problem)去了: 代码语言:javascript 代码运行次数:0 运行 复制 class Solution { public int strongPasswordChecker(String s) { int res...
For the purpose of this problem, we define empty string as valid palindrome. 【解答】注意大小写,注意数字和字母都要算有效字符。 代码语言:javascript 代码运行次数:0 运行 AI代码解释 public class Solution { public boolean isPalindrome(String s) { int left = 0; int right = s.length()-1; whil...
No.ProblemLeetCode力扣PythonGoSolutionDifficultyTag 0017 Letter Combinations of a Phone Number LeetCode 力扣 Python CSDN Medium 回溯、暴力 0034 Find First and Last Position of Element in Sorted Array LeetCode 力扣 Python CSDN Medium 二分 0039 Combination Sum LeetCode 力扣 Python CSDN Medium 回溯 ...
(,, ): HDU 1542 Atlantis update: query: HDU 1828 Picture update: query: Title Solution Difficulty Time Space O(n log 218. The Skyline Problem Go Hard O(n) n) 307. Range Sum Query - Go Hard O(1) O(n) Mutable 315. Count of Smaller O(n log Go Hard O(n) Numbers After Self ...
README.md single number ii Oct 21, 2015 solution.h the skyline problem Sep 8, 2015 Repository files navigation README Binary Tree Postorder Traversal (145) 要求不用递归实现后序遍历 后序是left-right-root,那么首先用修正的前序root-right-left,然后reverse一下,变成left-right-root就行了,代码如下...
The n-queens puzzle is the problem of placing n queens on an n×n chessboard such that no two queens attack each other. Given an integer n, return all distinct solutions to the n-queens puzzle. Each solution contains a distinct board configuration of the n-queens' placement, where 'Q' ...