1voidsetZeroes(vector<vector<int>>&matrix) {2intn = matrix.size(), m = matrix[0].size();3int*row = (int*)malloc((n /31+2) *sizeof(int));4int*col = (int*)malloc((m /31+2) *sizeof(int));57for(inti =0; i < n /31+2; i ++) row[i] =0;8for(inti =0; i < ...
matrix[i][j] = 0; } } delete [] rowFlags; delete [] colFlags; } }; 空间复杂度为O(1)的方法: class Solution { public: void setZeroes(vector<vector<int> > &matrix) { int m = matrix.size(); if(0 == m) return; int n = matrix[0].size(); // 按行遍历,把包含0的行中的...
Can you solve this real interview question? Set Matrix Zeroes - Given an m x n integer matrix matrix, if an element is 0, set its entire row and column to 0's. You must do it in place [https://en.wikipedia.org/wiki/In-place_algorithm]. Example 1: [
Can you solve this real interview question? Set Matrix Zeroes - Given an m x n integer matrix matrix, if an element is 0, set its entire row and column to 0's. You must do it in place [https://en.wikipedia.org/wiki/In-place_algorithm]. Example 1: [
public void setZeroes(int[][] matrix) { boolean left = false; boolean up = false; for (int i = 0; i < matrix.length; i++) { // 左边界是否有零 if (matrix[i][0] == 0) { left = true; } } for (int i = 0; i < matrix[0].length; i++) {// 上边界是否有零 ...
public void setZeroes(int[][] matrix) { //require int m=matrix.length; if(m<1) return; int n=matrix[0].length; Set<Integer> rowSet=new HashSet<Integer>(),colSet=new HashSet<Integer>(); //invariant for(int i=0;i<m;i++) ...
今天是LeetCode第42篇文章,我们来看看LeetCode第73题矩阵置零,set matrix zeroes。 这题的难度是Medium,通过率在43%左右,从通过率上可以看出这题的难度并不大。但是这题的解法不少,从易到难,有很多种方法。而且解法和它的推导过程都挺有意思,我们一起来看下。 题意 首先我们来看题意,这题的题意很简单,给定...
public static void setZeroes(int[][]matrix){ HashSet<Integer>row=new HashSet<>(); HashSet<Integer>col=new HashSet<>(); for (int i = 0; i < matrix.length; i++) { for (int j = 0; j < matrix[0].length; j++) {
对matrixi==0的部分,对i行、j列全部原地置为0. 2. 思路 找到第一个0的位置,将这个位置的行和列作为标记数组。 3. 代码 耗时:53ms class Solution { public: // 遍历找到第一个0,用这个0所在的行和列作为对应行列是否有0的标记位组。 void setZeroes(vector<vector<int>>& matrix) { ...
* * [73] Set Matrix Zeroes *//** * @param {number[][]} matrix * @return {void} Do not return anything, modify matrix in-place instead. */var setZeroes = function (matrix) { if (matrix.length === 0) return matrix; const m = matrix.length; const n = matrix[0].length;...