1classSolution:2#@param matrix, a list of lists of integers3#RETURN NOTHING, MODIFY matrix IN PLACE.4defsetZeroes(self, matrix):5#none case6ifmatrixisNone:7returnNone8#dimension of the matrix9ROW =len(matrix)10COL =len(matrix[0])11#record the status of first row and first column12fir...
原题地址:https://oj.leetcode.com/problems/set-matrix-zeroes/ 题意:Given amxnmatrix, if an element is 0, set its entire row and column to 0. Do it in place. 解题思路:分别记录两个向量x, y,保存行和列是否有0,再次遍历数组时查询对应的行和列然后修改值。 代码: classSolution:#@param matr...
publicclassSolution{publicvoidsetZeroes(int[][]matrix){intm=matrix.length;intn=matrix[0].length;inti,j;//先标记第一行和第一列是否有0booleanfirstRow=false,firstCol=false;for(j=0;j<n;j++){if(0==matrix[0][j]){firstRow=true;break;}}for(i=0;i<m;i++){if(0==matrix[i][0]){f...
Given a m x n matrix, if an element is 0, set its entire row and column to 0. Do it in place. answer: class Solution { public: void setZeroes(vector<vector<int>>& matrix) { set<int> mSet; set<int> nSet; int m = matrix.size(); if(m == 0) return; int n = matrix[0]...
Set Matrix Zeroes问题的时间复杂度是多少? Set Matrix Zeroes问题有哪些常见的解法? 73. Set Matrix Zeroes Given an m x n matrix. If an element is 0, set its entire row and column to 0. Do it in-place. Follow up: A straight forward solution using O(m**n) space is probably a bad id...
class Solution { public: void setZeroes(vector<vector<int> > &matrix) { int i,j; int num[330][330]; for(i=0;i<matrix.size();i++) { for(j=0;j<matrix[0].size();j++) { num[i][j]=matrix[i][j]; } } for(i=0;i<matrix.size();i++) { for(j=0;j<matrix[0].size...
代码(Python3) class Solution: def arithmeticTriplets(self, nums: List[int], diff: int) -> int: ans: int = 0 # num_set 维护 nums 中不同的数字,方便后续在 O(1) 内判断一个数字是否存在。 # (由于 nums 是严格单调递增的,所以 nums 中的数字必定全部各不相同) num_set: Set[int] = set...
代码(Python3) # 初始化全部元音字母的集合 VOWELS: Set[str] = set("aeiouAEIOU") class Solution: def halvesAreAlike(self, s: str) -> bool: n: int = len(s) # 如果 s 前一半子串和后一半子串的元音字母数相同,则满足题意 return Solution.count_vowels(s[:n>>1]) == Solution.count_vowels...
方法2排序比较 (三)创建一个Hashset,遍历整个数列,如果数字不在Hashset中,就在Hashset中新加入这个数字;如果在则直接输出True。若遍历完整个数列也没有相同数字,则输出False。 Time: O(n); Space: O(n) 方法3Hashset代码 思路学习自Youtube Neetcode大神:https://www.youtube.com/watch?v=3OamzN90kPg...
Repository files navigation README LeetCode Online Judge Algorithms DifficultyAccepted Easy 121 Medium 154 Hard 46 321/636 代码多数为 C/C++。如果是Java的话,那应该是我在实习的时候用Java练手提交的。还会乱入一些swift,那是因为Apple String标准库支持的方法比较全面。AboutLeet...