【Leetcode】 64. Minimum Path Sum 求最小路径和 方法1 DP法 递推方程很容易写 我们完全可以不用判断边界,如果边界越界时取的值为无限大,那么越界的元素则不会产生影响,我们通过让初始值为无限大即可,代码可以变得更简洁。注意第一个元素要单独赋值。 改进的DP O(n) space 我们发现DP中的二维数组,每次更新
Train tickets are sold inthree different ways: a1-daypass is sold forcosts[0]dollars, a7-daypass is sold forcosts[1]dollars, and a30-daypass is sold forcosts[2]dollars. The passes allow that many days of consecutive travel. For example, if we get a7-daypass on day2, then we can ...
classSolution{public:intmincostTickets(vector<int>& days,vector<int>& costs){intl = days.size();if(l ==0)return0;boolvis[366];memset(vis,0,sizeof(vis));for(autox : days) vis[x] =true;vector<int>dp(366,0x3f3f3f3f); dp[0] =0;for(inti=1; i<=365; i++) {if(vis[i] =...
In a country popular for train travel, you have planned some train travelling one year in advance. The days of the year that you will travel is given as an arraydays. Each day is an integer from1to365. Train tickets are sold in 3 different ways: a 1-day pass is sold forcosts[0]d...
题目地址:https://leetcode.com/problems/minimum-cost-for-tickets/ 题目描述 In a country popular for train travel, you have planned some train travelling one year in advance. The days of the year that you will travel is given as an array days. Each day is an integer from 1 to 365. ...
来源:力扣(LeetCode) 链接:https://leetcode-cn.com/problems/minimum-cost-for-tickets 著作权归领扣网络所有。商业转载请联系官方授权,非商业转载请注明出处。 2. 解题 dp[i] 表示第 i 天花的最少的钱 上一次花的钱是dp[days[i-1]],3种票的选择costs[k],后面相应的天数的总的花费为dp[days[i-1]]...
int mincostTickets(vector<int>& days, vector<int>& costs) { } }; 已存储 行1,列 1 运行和提交代码需要登录 Case 1Case 2 days = [1,4,6,7,8,20] costs = [2,7,15] 1 2 3 4 [1,4,6,7,8,20] [2,7,15] [1,2,3,4,5,6,7,8,9,10,30,31] [2,7,15] Source 布局...
String 1321-get-equal-substrings-within-budget 3617-find-the-original-typed-string-i Binary Search 1321-get-equal-substrings-within-budget Sliding Window 1321-get-equal-substrings-within-budget Prefix Sum 1321-get-equal-substrings-within-budget Dynamic Programming 1025-minimum-cost-for-ticketsAbout...
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